Electrostatic Equilibrium 20. A poor monkey spends his last nickel on two magic bananas. When he dangles the two9/3-kg (which is heavy because the magic bananas are made out of metal) bananas fromcords, they "magically" spread apart as shown below. Actually, it's because they have equalelectric charge.(A) Draw a FBD for each object (two in all). Label each force and the x- and y-coordinates.602.0 m2.0 m(B) Write the x- and y-sums for the forces acting on each object. There will be four sums.On the line immediately below each sum, rewrite the left-hand side in terms of the forces.(C) What is the tension in each cord?(D) What is the charge of each banana?

Given: Mass of metal banana, m=93Kg

(A) Draw a FBD for each object (two in all). Label each force and the x- and y-coordinates. 60 2.0 m 2.0 m (B) Write the x- and y-sums for the forces acting on each object. There will be four sums. On the line immediately below each sum, rewrite the left-hand side in terms of the forces. (C) What is the tension in each cord? (D) What is the charge of each banana?

(A) Draw a FBD for each object (two in all). Label each force and the x- and y-coordinates. 60 2.0 m 2.0 m (B) Write the x- and y-sums for the forces acting on each object. There will be four sums. On the line immediately below each sum, rewrite the left-hand side in terms of the forces. (C) What is the tension in each cord? (D) What is the charge of each banana?

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter18: Electric Charge And Electric Field

Section: Chapter Questions

Problem 26PE: (a) Two point charges q1 and q23.00 m apart, and their total charge is 20 C. (a) If the force of...

See similar textbooks

Similar questions

(a) Two point charges totaling 8.00 C exert a repulsive force of 0.150 N on one another when separated by 0.500 m. What is the charge on each? (b) What is the charge on each if the force is attractive?
(a) What is the electric field 5.00 m from die center of the terminal of a Van de Graaff with a 3.00-mC charge, noting that the field is equivalent to that of a point charge at the center of the terminal? (b) At this distance, what force does the field exert on a 2.00C charge on the Van de Graaff’s belt?
The charge unit length on the thin shown below is .What is the force on the point charge q? Solve this problem by first considering the electric force dF on q due to a small segment dx of the rod, which contains charge dx . Then, find the net force by integrating dF over the length of the rod.
There are very large numbers of charged particles in most objects. Why, then, don't most objects exhibit static electricity?
(a) Two point charges q1 and q23.00 m apart, and their total charge is 20 C. (a) If the force of repulsion between them is 0.075N, what are magnitudes of the two charges? (b) If one charge attracts the other with a force of 0.150 N, what are the magnitudes of the two charges? Note that you may need to solve a quadratic equation to reach your answer.
Panicle A of charge 3.00 104 C is at the origin, particle B of charge 6.00 104 C is at (4.00 m, 0), and panicle C of charge 1.00 104 C is at (0, 3.00 m). (a) What is the x-component of the electric force exerted by A on C? (b) What is the y-component of the force exerted by A on C? (c) Find the magnitude of the force exerted by B on C. (d) Calculate the x-component of the force exerted by B on C. (e) Calculate the y-component of the force exerted by B on C. (f) Sum the two x-components to obtain the resultant x-component of the electric force acting on C. (g) Repeat part (f) for the y-component. (h) Find the magnitude and direction of the resultant electric force acting on C.
(a) Find the total Coulomb force on a charge of 2.00 nC located at x = 4.00 cm in Figure 18.52 (b): given that q = 1,00C . (b) Find the x-position at which the electric field is zero in Figure 18.52 (b).
Earth has a net charge that produces an electric field of approximately 150 N/C downward at its surface, (a) What is the magnitude and sign of the excess charge, noting the electric field of a conducting sphere is equivalent to a point charge at its center? (b) What acceleration will the field produce on a free electron near Earth’s surface? (c) What mass object with a single extra electron will have its weight supported by this field?
(a) How strong is the attractive force between a glass rod with a 0.700 C charge and a silk cloth with a 0.600 C charge, which are 12.0 cm apart, using the approximation that they act like point charges? (b) Discuss how the answer to this problem might be affected if the charges are distributed over some area and do not act like point charges.
Assume the charged objects in Figure OQ23.10 are fixed. Notice that there is no sight line from the location of q2 to the location of q1. If you were at q1, you would be unable to see q2 because it is behind q3. How would you calculate the electric force exerted on the object with charge q1? (a) Find only the force exerted by q2 on charge q1. (b) Find only the force exerted by q3 an charge q1. (c) Add the force that q2 would exert by itself on charge q1 to the force that q3 would exert by itself on charge q1. (d) Add the force that q3 would exert by itself to a certain fraction of the force that q2 would exert by itself. (e) There is no definite way to find the force on charge q1.
Figure 18.44 shows an electric field extending over three regions, labeled I, II, and III. Answer the fallowing questions, (a) Are there any isolated charges? If so, in what region and what are their signs? (b) Where is the field strongest? (c) Where is it weakest? (d) Where is the field the most uniform?
Particle A of charge 3.00 104 C is at the origin, particle B of charge 6.00 101 C is at (4.00 m, 0), and particle C of charge 1.00 104 C is at (0, 3.00 in). We wish to find the net electric force on C. (a) What is the x component of the electric force exerted by A on C? (b) What is the y component of the force exerted by A on C? (c) Kind the magnitude of the force exerted by B on C. (d) Calculate the x component of the force exerted by B on C. (e) Calculate the y component of the force exerted by B on C. (f) Sum the two x components from parts (a) and (d) to obtain the resultant x component of the electric force acting on C. (g) Similarly, find the y component of the resultant force vector acting on C. (h) Kind the magnitude and direction of the resultant electric force acting on C.