A flywheel whose moment of inertia / = 200 lb-ft² is spinning at 180 RPM. For a flywheel, KE = Iw²/2, where w is the angular velocity, rad/s. Let g = 32.2 ft/s². Step 1 How high above the surface of the earth, in ft, would a 90 lb mass have to be raised to have its potential energy equal to the kinetic energy of the flywheel? h = i ft

icon
Related questions
Question
A flywheel whose moment of inertia / = 200 lb-ft² is spinning at 180 RPM. For a flywheel, KE = Iw²/2, where w is the angular velocity,
rad/s. Let g = 32.2 ft/s².
Step 1
How high above the surface of the earth, in ft, would a 90 lb mass have to be raised to have its potential energy equal to the kinetic
energy of the flywheel?
h = i
ft
Transcribed Image Text:A flywheel whose moment of inertia / = 200 lb-ft² is spinning at 180 RPM. For a flywheel, KE = Iw²/2, where w is the angular velocity, rad/s. Let g = 32.2 ft/s². Step 1 How high above the surface of the earth, in ft, would a 90 lb mass have to be raised to have its potential energy equal to the kinetic energy of the flywheel? h = i ft
Expert Solution
steps

Step by step

Solved in 2 steps with 2 images

Blurred answer