A gymnast with mass 48.0 kg stands on the end of a uniform balance beam as shown in the figure. The beam is 4.70 m long and has a mass of 270 kg (excluding the mass of the two supports). Each support is 0.590 m from its end of the beam. In unit-vector notation, what are the forces on the beam due to (a) support 1 and (b) support 2? L (a) Number i| (b) Number j Units j Units N N 21

Physics for Scientists and Engineers: Foundations and Connections
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Author:Katz, Debora M.
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Chapter14: Static Equilibrium, Elasticity, And Fracture
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Problem 31PQ: A wooden door 2.1 m high and 0.90 m wide is hung by two hinges 1.8 m apart. The lower hinge is 15 cm...
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A gymnast with mass 48.0 kg stands on the end of a uniform balance beam as shown in the figure. The beam is 4.70 m long and has a
mass of 270 kg (excluding the mass of the two supports). Each support is 0.590 m from its end of the beam. In unit-vector notation,
what are the forces on the beam due to (a) support 1 and (b) support 2?
L
(a) Number i|
(b) Number
j Units
j Units
N
N
21
Transcribed Image Text:A gymnast with mass 48.0 kg stands on the end of a uniform balance beam as shown in the figure. The beam is 4.70 m long and has a mass of 270 kg (excluding the mass of the two supports). Each support is 0.590 m from its end of the beam. In unit-vector notation, what are the forces on the beam due to (a) support 1 and (b) support 2? L (a) Number i| (b) Number j Units j Units N N 21
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