(a) Let n be a positive integer, and let t₁, ..., tn be positive numbers satisfying t₁+...+tn = 1. If I is an interval and f: IR is concave down, show that for any ₁,...,n in I, t₁x₁ + ...+ tnxn is in I, and f(t₁x₁ + + tnxn) ≥tif(x₁) + + tnf(xn). (b) The arithmetic mean geometric mean inequality says that if a₁, ..., an are n positive num- bers, then statements. a₁ + + an n > a₁...an. Use the concavity of a suitable function to prove this inequality. You need to justify all the

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
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Chapter7: Distance And Approximation
Section7.4: The Singular Value Decomposition
Problem 54EQ
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Question
(a) Let n be a positive integer, and let t₁,
1,..., tn be positive numbers satisfying t₁+...+tn = 1.
If I is an interval and f: I→ R is concave down, show that for any ₁,...,n in I,
+ tnxn is in I, and
t₁x₁ +
f(t₁x₁ +... + tnxn) ≥ t₁f(x₁) +...+ tnf(xn).
(b) The arithmetic mean geometric mean inequality says that if a₁, ..., an are n positive num-
bers, then
a₁ + ... + an
n
> va₁...an.
Use the concavity of a suitable function to prove this inequality. You need to justify all the
statements.
Transcribed Image Text:(a) Let n be a positive integer, and let t₁, 1,..., tn be positive numbers satisfying t₁+...+tn = 1. If I is an interval and f: I→ R is concave down, show that for any ₁,...,n in I, + tnxn is in I, and t₁x₁ + f(t₁x₁ +... + tnxn) ≥ t₁f(x₁) +...+ tnf(xn). (b) The arithmetic mean geometric mean inequality says that if a₁, ..., an are n positive num- bers, then a₁ + ... + an n > va₁...an. Use the concavity of a suitable function to prove this inequality. You need to justify all the statements.
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