1.A long cylindrical shellouter radiusR₂ = 2 cmisshownincylindricalshellistemperature Ti=10 c° and outer wallatConstant temperature T₂ = 20 C°Calculate the temperature at r= 1.5 cm(Considerconduction only)Assumptions:system isThermalinGiven: Theof innerandthe figure. Theradial+The differentialThe system is:J²Tdr²rmaintained atsteady stateconductivity, K = 22.5 w/mc,system follows Fourier's law of heatHeat loss in axial direction is negligible.JTdrradius Ri=1cmLength L=lominnerWallConstantis maintained= 0ofisTiRIR₂constant.conduction.equation representingTz

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A long cylindrical shell outer radius R₂ = 2 cm is shown in cylindrical shell temperature Ti=10 c" and outer Wall at constant temperature T₂ = 20 C² Calculate the temperature at r= 1.5 cm ( Consider conduction only) • in of inner radius R₁=1cm and the figure. The radial + is maintained at Given: The differential The system is: I JT J²T dr² r dr Length L=lom inner Assumptions: system is steady state • Thermal conductivity, K = 22.5 w/mc, is • system follows Fourier's law of heat Heat loss in axial direction = 0 Wall of Constant is maintained Ti R₁ Rz constant. conduction. is negligible. equation representing Tz

A long cylindrical shell outer radius R₂ = 2 cm is shown in cylindrical shell temperature Ti=10 c" and outer Wall at constant temperature T₂ = 20 C² Calculate the temperature at r= 1.5 cm ( Consider conduction only) • in of inner radius R₁=1cm and the figure. The radial + is maintained at Given: The differential The system is: I JT J²T dr² r dr Length L=lom inner Assumptions: system is steady state • Thermal conductivity, K = 22.5 w/mc, is • system follows Fourier's law of heat Heat loss in axial direction = 0 Wall of Constant is maintained Ti R₁ Rz constant. conduction. is negligible. equation representing Tz

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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