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Name: 1. A mutant allele in persons with familial hypercholesterolemia (FH)
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Description: 1. A mutant allele in persons with familial hypercholesterolemia (FH) causes death due to a lack of liver receptors for LDL. Susceptible persons have half the normal number of receptors, while other individuals have the normal number of receptors. In

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Biology

A mutant allele in persons with familial hypercholesterolemia (FH) causes death due to a lack of liver receptors

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter12: Genes And Cancer

Section: Chapter Questions

Problem 12QP

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2. Hemophilia is an X linked recessive trait. There is a woman who is a carrier for hemophilia and marries a man with hemophilia. a) Complete the Punnett Square (it is a google drawing so you will have to double click it to go to the drawing and type in and around the square. Hold the CONTROL (or Command) button and press the PERIOD button to write a superscript/exponent.) b) What are the possible genotypes of the children? c) Could any of their children have hemophilia? If so, would the child be male or female? Explain your reasoning.
A mutant allele in persons with familial hypercholesterolemia (FH) causes death due to a lack of liver receptors for LDL. Susceptible persons have half the normal number of receptors, while other individuals have the normal number of receptors. In a phenotypically normal couple, the man had a female 1 cousin (on his father’s side) who died from FH; the woman had a maternal uncle with FH. a. What is the probability that neither of the couple might be susceptible. b. What is the probability that one of them might be susceptible, but the other is not. c. What is the probability that they will have an FH child if a test discloses that both of them are susceptible.
3. Short-tailed pup distribution. In mice, the dominant T allele results in a short tail. Homozygous T/T genotype is lethal, which means mouse embryos with this genotype die before they are born. Homozygous t/t is normal, with normal tail. A cross between two short-tailed mice produces a litter of 5 pups. a). What are the genotype(s) of the two short-tailed mice used in the cross? b). What are the possible genotypes and phenotypes of the 5 pups? What are their perspective ratio?
1. In humans, hemophilia is a sex linked trait. Females can be normal, carriers, or have the disease. Males will have the disease or not (but they won't be ever carriers) XH XH = female, normal XH Xh = female, carrier Xh Xh = female, hemophilic XH Y = male, normal Xh Y = male, hemophilic a) Show the cross of a man who has hemophilia with a woman who is a carrier. b) What is the probability that their children have the disease
A mutant allele in persons with familial hypercholesterolemia (FH) causes death due to a lack of liver receptors for LDL. Susceptible persons have half the normal number of receptors, while other individuals have the normal number of receptors. In a phenotypically normal couple, the man had a female 1 cousin (on his father’s side) who died from FH; the woman had a maternal uncle with FH. Using standard symbols, draw apedigree of these couple’s families. Write the genotypes of each family member.
Given these parents-note, they are NOT quite the same as each other!: mom = Aa Bb Cc Dd dad = Aa Bb cc Dd NOTE that the A gene acts incompletely dominantly. a) What chance does their baby having the "strongest phenotype" in A, being recessive in b, recessive in c, and dominant in D? Give one fraction. Show work. b) phenotype? Now assume mom was CC instead of Cc. Now what is the chance of having that same
A mutant allele in persons with familial hypercholesterolemia (FH) causes death due to a lack of liver receptors for LDL. Susceptible persons have half the normal number of receptors, while other individuals have the normal number of receptors. In a phenotypically normal couple, the man had a female 1 cousin (on his father’s side) who died from FH; the woman had a maternal uncle with FH. a. Calculate the probability that neither of the couple might be susceptible. b. Calculate the probability that one of them might be susceptible, but the other is not. c. Calculate the probability that they will have an FH child if a test discloses that both of them are susceptible.
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4.) A man and a woman have a child. The father is blood type A, and one of his parents was blood type A and the other was blood type O. The mother is blood type B, and one of her parents was blood type B, the other type O. Both the father and the mother are carriers of the Bombay allele. (Neither of the type-O grandparents were type O because of the Bombay allele – they had the regular type O genotype.) WhataretheoddsthattheirbabywillhavebloodtypeO? WhataretheoddsthattheirbabywillhavebloodtypeAB? (Hint – for this question, you should draw out a pedigree and fill in as much as you can for the genotypes of BOTH genes that are involved.)
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12. A. B. C. A certain type of migraine headache (M) is dominant to no migraines (m). What is the genotype of a man who has migraine headaches if his father did not have them? What is the genotype of a man who has migraine headaches if his mother did not have them? If a woman without migraines marries a man who is heterozygous for migraines, what would you expect for the genotypes and phenotypes of their children? If two people who are heterozygous for migraines marry and have children, what would you expect for the genotypes and phenotypes of the children.