Also determine if the particle is slowing downor speeding up at t=4 because velocity andacceleration have the same sign or opposite Particle Motion from Equation (Level 1)Oct 22, 11:50:58 PMA particle moves along the x-axis so that attime t 0 its position is given byx(t) = −t³ + 5t² + 13t. Determine if theparticle is speeding up or slowing down att = 4.Since v (4)=the particle isthave=and a(4)=0at4 because velocity and acceleration

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A particle moves along the x-axis so that at time t 0 its position is given by x(t) = −t³ + 5t² + 13t. Determine if the particle is speeding up or slowing down at t = 4. Since v(4) = = and a(4) = the particle is t = 4 because velocity and acceleration have î at

A particle moves along the x-axis so that at time t 0 its position is given by x(t) = −t³ + 5t² + 13t. Determine if the particle is speeding up or slowing down at t = 4. Since v(4) = = and a(4) = the particle is t = 4 because velocity and acceleration have î at

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter2: Motion In One Dimension

Section: Chapter Questions

Problem 21P

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Question

Also determine if the particle is slowing down or speeding up at t=4 because velocity and acceleration have the same sign or opposite

Particle Motion from Equation (Level 1)
Oct 22, 11:50:58 PM
A particle moves along the x-axis so that at
time t 0 its position is given by
x(t) = −t³ + 5t² + 13t. Determine if the
particle is speeding up or slowing down at
t = 4.
Since v (4)
=
the particle is
t
have
=
and a(4)
=
0
at
4 because velocity and acceleration

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