A proton is placed in an electric field of intensity 400 N/C. What are the magnitude and direction of the acceleration of this proton = 1.67 x 1027 kg. e = 1.60 x 10-19 c) proton due to this field? (m O 38.3 x 1010 m/s? in the direction of the electric field O 3.83 x x 1010 m/s? in the direction of the electric field O 3.83 x 10° m/s opposite to the electric field O 38.3 x 1010 m/s opposite to the electric field 3.83 x 1010 m/s? opposite to the electric field

Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter24: Electric Fields
Section: Chapter Questions
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A proton is placed in an electric field of intensity 400 N/C. What are the magnitude and direction of the acceleration of this proton
due to this field? (m
= 1.67 x 102 kg, e = 1.00 x 10-19 C)
proton
38.3 x 1010 m/s in the direction of the electric field
3.83 x 1010 m/s in the direction of the electric field
O 3.83 x 10" m/s opposite to the electric field
38.3 x 1010 m/s opposite to the electric field
O 3.83 x 1010 m/s? opposite to the electric field
Transcribed Image Text:A proton is placed in an electric field of intensity 400 N/C. What are the magnitude and direction of the acceleration of this proton due to this field? (m = 1.67 x 102 kg, e = 1.00 x 10-19 C) proton 38.3 x 1010 m/s in the direction of the electric field 3.83 x 1010 m/s in the direction of the electric field O 3.83 x 10" m/s opposite to the electric field 38.3 x 1010 m/s opposite to the electric field O 3.83 x 1010 m/s? opposite to the electric field
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