A resonating glass tube closed at one end is 4 cm wide and 47 cm long. What are the frequencies and wavelengths of the first three harmonics for the resonating tube? The speed of sound in air is 343 m/s. Remember to include the following when answering these questions: What did you get? (your answer with the correct units and supporting work) How did you get that? (the equation you chose to use to get your answer) Why did you use that? (the concept that supports the use of the equation that you chose to use)
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A resonating glass tube closed at one end is 4 cm wide and 47 cm long. What are the frequencies and wavelengths of the first three harmonics for the resonating tube? The speed of sound in air is 343 m/s.
Remember to include the following when answering these questions:
What did you get? (your answer with the correct units and supporting work)
How did you get that? (the equation you chose to use to get your answer)
Why did you use that? (the concept that supports the use of the equation that you chose to use)
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- The diaphragm of a speaker, 20 cm in diameter, vibrates with a frequency of 900 Hz and an amplitude of 0.01 mm. Assuming that the air molecules near the diaphragm have this same amplitude of vibration. Determine the sound intensity just in front of the diaphragm. (Step 1 identify the data. Step 2 pose the formula. Step 3 exercise.)A wave is modeled by the wave function: y (x, t) = A sin [ 2π/0.1 m (x - 12 m/s*t)] 1. Find the wavelength, wave number, wave velocity, period and wave frequency. 2. Construct on the computer, in the same graph, the dependence of y (x, t) from x on t = 0 and t = 5 s in case the value of amplitude A corresponds to the first letter of your name: letter E A. A=0.1 mB. A=0.15 mC. A=0.2 mÇ. A=0.25 mD. A=0.3 mDh. A=0.35 mE. A=0.4 mË. A=0.45 mF. A=0.5 m G. A=0.55 mGj. A=0.6 mH. A=0.65 mI. A=0.7 mJ. A=0.75 mK. A=0.8 mL. A=0.85 mLl. A=0.9 mM. A=0.95 m N. A=1.05 mNj. A= 1.1 mO. A=1.15 mP. A=1.2 mQ. A=1.25 mR. A=1.3 mRr. A=1.35 mS. A=1.4 mSh. A=1.45 m T. A=1.5 mTh. A=1.55 mU. A=1.6 mV. A=1.65 mX. A=1.7 mXh. A=1.75 mY. A=1.8 mZ. A=1.85 mZh. A=1.9 m 3. After constructing the graph, make the appropriate interpretations and comments from the result that you got graphically. 4. How much is the wave displaced during the time interval from t = 0 to t = 5 s? Does it match this with the graph results?…There is a long steel wire of length 4.31 m where its upper end is attached to the ceiling. At the other end, a 57.6 kg object is suspended. It is observed that it takes a transverse pulse 0.0232 s to travel from the bottom to the top of the wire. What is the mass of the wire? NOTE: Final answer in THREE decimal places. Include the unit. Round your answer to 3 decimal places. Add your answer
- A wave is modeled by the wave function: y (x, t) = A sin [ 2π/0.1 m (x - 12 m/s*t)] 1. Find the wavelength, wave number, wave velocity, period and wave frequency. 2. Construct on the computer, in the same graph, the dependence of y (x, t) from x on t = 0 and t = 5 s and the amplitude is A=0.4m. 3. After constructing the graph, make the appropriate interpretations and comments from the result that you got graphically. 4. How much is the wave displaced during the time interval from t = 0 to t = 5 s? Does it match this with the graph results? Justify your answer. Is the material transported long wave displacement? If yes, how much material is transported over time interval from t = 0 to t = 5 s? Comment on your answer. We now consider two sound waves with different frequencies which have to the same amplitude. The wave functions of these waves are as follows: y1 (t) = A sin (2πf1t) y2 (t) = A sin (2πf2t) 5. Find the resultant wave function analytically. 6. Study how the resulting wave…The flute is typically about 26 inches long and as we have seen this week it is an open tube at both ends. There are holes that are closed or opened by fingering and valves that change their effective length, and the pattern and mechanisms to do this set various designs of flutes played now and in the past. Assume that the velocity of sound in warm moist air is 340 m/s. 1. Take a bottle with a narrow opening that had your favorite beverage in it, and when it is empty blow across the top of the bottle. Now add some water so that the bottom of the bottle is covered and the air space is less with the bottle still vertical. Blow on that across the top. Does the pitch (frequency) of the resonant sound increase or decrease? You can try it yourself, and then explain what you found.A wave is modeled by the wave function: y (x, t) = A sin [ 2π/0.1 m (x - 12 m/s*t)] 1. Find the wavelength, wave number, wave velocity, period and wave frequency. 2. Construct on the computer, in the same graph, the dependence of y (x, t) from x on t = 0 and t = 5 s and the value of amplitude A=0.4m. 3. After constructing the graph, make the appropriate interpretations and comments from the result that you got graphically. 4. How much is the wave displaced during the time interval from t = 0 to t = 5 s? Does it match this with the graph results? Justify your answer. Is the material transported long wave displacement? If yes, how much material is transported over time interval from t = 0 to t = 5 s? Comment on your answer. We now consider two sound waves with different frequencies which have to the same amplitude. The wave functions of these waves are as follows: y1 (t) = A sin (2πf1t) y2 (t) = A sin (2πf2t) 5. Find the resultant wave function analytically. 6. Study how the resulting…
- A wave is modeled by the wave function: y (x, t) = A sin [ 2π/0.1 m (x - 12 m/s*t)] 1. Find the wavelength, wave number, wave velocity, period and wave frequency. 2. Construct on the computer, in the same graph, the dependence of y (x, t) from x on t = 0 and t = 5 s and the value of amplitude A=0.4m. 3. After constructing the graph, make the appropriate interpretations and comments from the result that you got graphically. 4. How much is the wave displaced during the time interval from t = 0 to t = 5 s? Does it match this with the graph results? Justify your answer. Is the material transported long wave displacement? If yes, how much material is transported over time interval from t = 0 to t = 5 s? Comment on your answer.A tuning fork is held a certain distance from your ears and struck. Your eardrums’ vibrations after t seconds are given by p = 3 sin 2t. When a second tuning fork is struck, the formula p = 2sin(2t + π) describes the effects of the sound on the eardrums’ vibrations. The total vibrations are given by p = 3 sin 2t + 2 sin(2t + π). Solve, a. Simplify p to a single term containing the sine. b. If the amplitude of p is zero, no sound is heard. Based on your equation in part (a), does this occur with the two tuning forks in this exercise? Explain your answer.An air column L = 1.97 m in length is open at both ends. The frequency of a certain harmonic is 410 Hz, and the frequency of the next higher harmonic is 492 Hz. %3D Part 1) Determine the speed of sound in the air column. U = m/s Part 2) For the answer you found in part 1, what is the fundamental frequency of the air column if one of its ends were closed? fi = Hz %3D Part 3) (independent of other parts) An astronaut on the Moon wishes to measure the local value of g by timing pulses traveling down a wire that has a large mass M kg suspended from one end. Assume the wire is Im long and has a mass m kg. A pulse requires ts to traverse the length of the wire. Find an expression (algebraic) for g in terms of the other variables given in the problem. (You can neglect the mass of the wire when calculating the tension in it.) m/s?
- Tube Tuning Fork A tuning fork vibrating at 512HZ is held near one end of a tube of length L that is open at both ends, as shown above. The column of air in the tube resonates at its fundamental frequency. The speed of sound in air is 340m/s. (a) Calculate the length L of the tube. (b) The column of air in the tube is still resonating at its fundamental frequency. Copy the axes below on to your own paper, and then sketch a graph of the maximum speed of air molecules as they oscillate in the tube, as a function of position x, from x-0 (left end of tube) to x=L (right end of tube). (Ignore random thermal motion of the air molecules.) Hint, you are essentially mapping out where the node(s) are. L/4 L/2 3L/4 M DELL Maximum Particle SpeedThe flute is typically about 26 inches long and as we have seen this week it is an open tube at both ends. There are holes that are closed or opened by fingering and valves that change their effective length, and the pattern and mechanisms to do this set various designs of flutes played now and in the past. Assume that the velocity of sound in warm moist air is 340 m/s. 1. A flute player can also create higher frequencies by generating harmonics of the fundamental. With no holes open, by blowing harder on it, vibrations with shorter wavelengths will resonate in the tube. Again, thinking of the physics as a tube open at both ends without open holes otherwise, the fundamental has a wavelength that is twice the length of the tube. What are the wavelengths of the first and second harmonics? Explain how you figured that out. 2.Take a bottle with a narrow opening that had your favorite beverage in it, and when it is empty blow across the top of the bottle. Now add some water so that…A wave of amplitude 0.5 m interferes with a wave of amplitude of 0.2m. What is the maximum resultant displacement that may occur? What is the minimum resultant displacement that may occur? Draw a picture for each.