A rod with a diameter of 13 mm and a length of 50 mm is subjected to a force of 50 kN. The diameter is reduced to 12.99265 mm. Determine:  a. The modulus of elasticity. Answer: 200 GPa.  b. Poisson's ratio. Answer: ν = 0.30  c. Shear modulus. Answer: G = 76.92 GPa.  d. The deformation of the rod. Answer: δx = 0.09415 mm. Recommendation: Obtain the modulus of elasticity using the slope of the straight line.

Engineering Fundamentals: An Introduction to Engineering (MindTap Course List)
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Author:Saeed Moaveni
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Chapter20: Engineering Economics
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A rod with a diameter of 13 mm and a length of 50 mm is subjected to a force of 50 kN. The diameter is reduced to 12.99265 mm. Determine: 
a. The modulus of elasticity. Answer: 200 GPa. 
b. Poisson's ratio. Answer: ν = 0.30 
c. Shear modulus. Answer: G = 76.92 GPa. 
d. The deformation of the rod. Answer: δx = 0.09415 mm.

Recommendation: Obtain the modulus of elasticity using the slope of the straight line.

(MPa)
400
€(mm/mm)
0.002
Transcribed Image Text:(MPa) 400 €(mm/mm) 0.002
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