A sample of water from a river was analyzed by titrating a 125 mL aliquot with 0.0210 M EDTA, consuming 22.52 mL. Express the hardness of the water in ppm of CaCO3.
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A sample of water from a river was analyzed by titrating a 125 mL aliquot with 0.0210 M EDTA, consuming 22.52 mL. Express the hardness of the water in ppm of CaCO3.
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- A 15.00 mL sample of hard water was titrated with a 0.0150 M EDTA solution. The titration required 26.72 mL of EDTA to reach the end point. What is the total hardness concentration of the water sample in ppm?Titration of Ca2+ and Mg2+ in a 50.00-mL sample of hard water required 23.65 mL of 0.01205 M EDTA. A second 50.00-mL aliquot was made strongly basic with NaOH to precipitate Mg2+ as Mg(OH)2(s). The supernatant liquid was titrated with 14.53 mL of the EDTA. Calculate the concentration in ppm of CaCO3 in the sample. Calculate the concentration in ppm of MgCO3 in the sample.Titration of Ca²+ and Mg²+ in a 50.00-mL hard water sample required 23.65 mL of 0.01205 M EDTA. A second 50.00-mL aliquot was made strongly basic with NaOH to precipitate Mg²+ as Mg(OH)2(s). The supernatant liquid was titrated with 14.53 mL of the EDTA solution. Calculate the total hardness of the water sample, expressed as ppm CaCO3.
- A mixture containing iodide is analyzed by the Volhard method. 0.6712 g of the sample is reacted with 50.00 mL of 0.05619 M AGNO3. The precipitate formed is removed by filtration and the excess Ag+ is back titrated with KSCN 0.05322 M, requiring 35.15 mL to reach the end point. Calculate the concentration of iodide in the sample in parts per million (mg/kg).A mixture containing only KCl and NaBr is analyzed by the Mohr method. A 0.5072-g sample is dissolved in 50 mL of water and titrated to the Ag2CrO4 end point, requiring 36.85 mL of 0.1120 M AgNO3. A blank titration requires 0.71 mL of titrant to reach the same end point. Report the %w/w KCl and NaBr in the sample.KCl = 74.551 NaBr = 102.89An aliquot of 20 ml of skim milk was placed in an Erlenmeyer flask. To the flask was added 3 to 4 drops of phenolphthalein. The sample was titrated in triplicate using a previously standardized NaOH solution 0.101M. The volumes of NaOH spent in the three experiments to reach chemical equivalence were 3.6ml, 3.7ml and 3.5ml. 1) Express the acidity of milk in g/L of lactic acid. 2) Assuming that the only acid present in milk is lactic acid, would you expect the pH corresponding to the equivalence point was 7?.
- Direct titration: 10.90 ± 0.02 mL of an unknown KHP solution required 11.72 ± 0.02 mL of 0.1090 ± 0.0006 M NaOH to reach the end point. What is the concentration of KHP in the unknown solution reported with absolute uncertainty? If the unknown solution was prepared by dissolving 5.128 g of the unknown KHP (204.22 g/mol) in 100.00 mL of water, what is the weight percent of KHP in the sample?A mixture containing only KCl and NaBr is analyzed by the Mohr method. A 0.2125- g sample is dissolved in 25 mL of water and titrated to the Ag2CrO4 end point, requiring 25.63 mL of 0.1110 M AgNO3. A blank titration requires 1.15 mL of titrant to reach the same end point. Report the %w/w KCl and NaBr in the sample.KCl = 74.551 NaBr = 102.89A 1.43 x 10-4 L solution of 45.7 mg/mL protein was analyzed using the Kjeldahl procedure. After digestion of the protein, the liberated NH3 was collected in 9.80 mL of 0235 M HCl. The unreacted acid required 10.75 mL of a standard solution of 0.0149 M NaOH for complete titration. Calculate the weight percent of nitrogen in the protein. (Molar mass N = 14.00674 g/mol)
- A 0.1064-g of aldrin pesticide sample was decomposed and the liberated chloride was extracted using water. It was titrated with 23.28 mL of 0.03337 M AgNO 3 using a chromate indicator. Express results in % aldrin (C 12H 8Cl 6, MM=365). 17.28 % 22.12 % 44.42 % 63.21 %If you titrate 50 mL of a sample with 0.06 N EDTA and the titration takes 12.4 mL of EDTA to reach the endpoint, what is the hardness of the sample in ppm as CaCO3?Identify the nature of the water sample from the hardness value.If a 35.0-mL water sample required 10.25 mL of 0.0150 M EDTA solution to reach equivalence point, what’s the hardness of the water sample in ppm CaCO3 (FW 100.1 g/mol)?