A series of modified Proctor tests have been performed on a soil that has a Gs of 2.68.The test results obtained are as follows.PointNo.Weight ofCompacted Soil +Mass ofMass of Can +Moisture Content Test ResultsMass of Can + DryMold (lb)Can (g)Moist Soil (g)18.7322.13207.5129.0725.26239.6939.4019.74253.9049.4623.36250.9359.2220.28301.47Soil (g)202.30225.27230.64219.74250.95The weight of the empty mold was 5.06 lb.Plot the laboratory test results and the S = 80% and S = 100% curves, and thendraw the modified Proctor compaction curve. Determine the maximum dry unit weight(lb/ft³) and the optimum moisture content, based on the modified Proctor test.Assuming that the field compaction curve is the same as the compaction curveobtained using the modified Proctor test, determine the range of as-compacted moisturecontent required in the field to obtain a relative compaction of at least (a) 90%, and (b)95%.

max dry unit weight = 11.68lb/cu ft and optimum moisture content =11.03 % Explanation:Step 1we know…

Answered: A series of modified Proctor tests have…

Principles of Geotechnical Engineering (MindTap Course List)

9th Edition

ISBN:9781305970939

Author:Braja M. Das, Khaled Sobhan

Publisher:Braja M. Das, Khaled Sobhan

Chapter4: Plasticity And Structure Of Soil

Section: Chapter Questions

Problem 4.3P

See similar textbooks

Question

A series of modified Proctor tests have been performed on a soil that has a Gs of 2.68.
The test results obtained are as follows.
Point
No.
Weight of
Compacted Soil +
Mass of
Mass of Can +
Moisture Content Test Results
Mass of Can + Dry
Mold (lb)
Can (g)
Moist Soil (g)
1
8.73
22.13
207.51
2
9.07
25.26
239.69
3
9.40
19.74
253.90
4
9.46
23.36
250.93
5
9.22
20.28
301.47
Soil (g)
202.30
225.27
230.64
219.74
250.95
The weight of the empty mold was 5.06 lb.
Plot the laboratory test results and the S = 80% and S = 100% curves, and then
draw the modified Proctor compaction curve. Determine the maximum dry unit weight
(lb/ft³) and the optimum moisture content, based on the modified Proctor test.
Assuming that the field compaction curve is the same as the compaction curve
obtained using the modified Proctor test, determine the range of as-compacted moisture
content required in the field to obtain a relative compaction of at least (a) 90%, and (b)
95%.

Expert Solution

Step by step

Solved in 1 steps

SEE SOLUTION Check out a sample Q&A here

Similar questions

5.5 The modified Proctor test (ASTM D 698, method C) was performed for a soil with G, = 2.70, and the results are as follows: Moist Weight Content, % in Mold, gf Water 6.5 3250 9.3 3826 12.6 4293 14.9 4362 17.2 4035 18.6 3685 (a) Plot the Ya versus w relation. (b) Determine Ya,max and wopt- (c) Calculate S and e at the maximum dry unit weight point.
Find the missed data and give the result of Fineness Modulus of sample soil data given below. Weight Percentage Cumulative Percentage finer Sieve retained Weight retained percentage N = (100 - C) S.NO size retained (C) Select one: (gm) (gm) O a. 7.824 1 75mm O b. 9.438 63mm O c. 8.142 3 50mm O d. 7.649 4 37.5mm 28mm 123 6.15 6.15 6 20mm 107 5.35 11.50 7 14mm 208 10.4 21.9 8 10mm 56 2.8 24.7 6.3mm 3.9 10 5.0mm 92 4.6 33.2 11 3.35mm 308 15.4 48.6 12 2.0mm 223 11.15 59.75 13 1.18mm 188 9.4 69.15 14 600µ 282 14.1 83.25 15 300µ 96 4.8 88.05 16 150µ 88 4.4 92.45 17 75µ 103 5.15 97.6 18 pan 48 2.4 100
Calculate the CEC (m.e./100g soil) using the following given miliequivalent weights obtained from a 25g soil sample (a. Ca++= 2.23 m.e; b. Mg++=1.32 m.e.; c. Na+= 1.98 m.e.; d. K+= 1.87 m.e.; e. H+= 1.27 m.e.; f. Al+++= 0.11 m.e.; g. NH4+= 2.3 m.e.; h. NO3-= 1.5 m.e.
Find the value of Cc of the following soil data sample Weight Percentage Cumulative Percentage Sieve Weight retained (gm) percentage retained (C) retained finer S.NO Select one: O a. 10.85 size (gm) N = (100 - C) {W,/ W,} x 100 1 75mm 100 O b. 7.36 63mm 100 O c. 18.34 50mm 100 O d. 2,96 4 37.5mm 454 22.7 22.7 77.30 5 28mm 285 14.25 36.95 63.05 6 20mm 207 10.35 47.30 52.70 7 14mm 318 15.90 63.20 36.80 8 10mm 206 10.30 73.50 26.50 6.3mm 118 5.90 79.40 20.60 10 5.0mm 102 5.10 84.50 15.50 11 3.35mm 64 3.20 87.70 12.30 12 2.0mm 88 4.40 92.10 7.90 13 1.18mm 35 1.75 93.85 6.15 14 600µ 42 2.10 95.15 4.85 15 300µ 33 1.65 97.60 2.40 16 150µ 18 0.90 98.50 1.50 17 75µ 22 1.10 99.6 0.40 18 Pan 8 0.40 100 In the pan we have = 100 W,= 2000 2 -99.6 = 0.4 % of material 2. 3.
During Atterberg limit tests in the soil mechanics laboratory, the students obtained the following results from a clayey soil. Number of Blows (N) Moisture Content (%) 14 38.4 16 36.5 20 33.1 28 27.0 Plastic limit tests: Students conducted two trials and found that PL = 17.2% for the first trial and PL = 18.4% for the second trial. Assume that the liquid limit of the soil is . LL = 29.0% a. Determine the flow index. b. Determine the liquidity index of the soil if the in situ moisture content is 22.0%.
A sample of field soil is tested in the laboratory. The results of Standard and Modified Proctor tests at optimum moisture content are given in the Table below: Standard Proctor test Modified Proctor test Mass of wet soil in the mold (g) 1800 2000 Volume of Proctor mold (cm?) 900 1000 Optimum moisture content (%) 12 10 At the field, a sample of 600 cm3 of this soil weighted 1200 g. The weight of water in this sample was 200 g. Find the following: 1- Degree of compaction (Relative compaction) (R%) at Standard Proctor test. 2- Degree of compaction (Relative compaction) (R%) at Modified Proctor test.
A sample of field soil is tested in the laboratory. The results of Standard and Modified Proctor tests at optimum moisture content are given in the Table below: Standard Proctor test Modified Proctor test Mass of wet soil in the mold (g) 1800 2000 Volume of Proctor mold (cm2) 900 1000 Optimum moisture content (%) 12 10 At the field, a sample of 600 cm3 of this soil weighted 1200 g. The weight of water in this sample was 200 g. Find the following: 1- Degree of compaction (Relative compaction) (R%) at Standard Proctor test. 2- Degree of compaction (Relative compaction) (R%) at Modified Proctor test.
B. ( A Soil Specimen has the following characteristics: % passing No.4 sieve = 85 % passing No.200 sieve = 11 D60 = 2 mm D30 = 0.35 mm D10 = 70 μm L.L = 36% P.L = 31% D8 = 2 μm 1. Classify the specimen according to the Unified Soil Classification System (USCS). Assign the group name and the group symbol. 2. Determine the soil activity. 3. Determine the soil Liquidity index and consistency index if we = 26%. J
A fine-grained soil has 60% clay with LL 220%, PL 545%, and a natural water content of 6%. Astandard Proctor test was carried out in the laboratory and the following data were recordedDiameter of mold = 101.40 mm Height of mold = 116.70 mm Mass of mold = 4196.50 gram Specific gravity, Gs = 2.69 a) What field equipment would you specify to compact the soil in the field, and why?b) How would you check that the specified dry unit weight and water content are achievedin the field?
The modified Proctor test (ASTM D 698, method C) was performed for a soil with G, = 2.70, and the results are as follows: Moist Weight in Mold, gf Water Content, % 6.5 3250 9.3 3826 12.6 4293 14.9 4362 17.2 4035 18.6 3685 (a) Plot the Ya versus w relation. (b) Determine Ya.max and wopt• (c) Calculate S and e at the maximum dry unit weight point. (d) What is Y at w. (e) What is the range of water content if the relative compaction (R.C.) is required to be 95% of the modified Proctor Ya.max? pt? opr?
2. The coefficient of permeability for a fine-grained soil is determined in the laboratory by use of a falling head test. Test conditions and results are as indicated below. Determine the coefficient of permeability, then indicate the probable soil classification. - Length of soil sample = 150mm - Cross-sectional area of standpipe = 200mm2 - Cross-sectional area of soil sample = 1,140mm2 - At the start of the test, the water level in the supply standpipe is 0.95m above the top of the permeameter. - %3D Draw the sketch. Reference Table for Soil Classification Soil Type k, Coefficient of Permeability (mm/sec) Clean Gravel 10 - 100 Clean Sand and Gravel mixture none Fine sand.silt 10-2 to 10-4 Sand Silt Clay 10-3 to 10-6 Glacial < 10-6
A specific gravity test was performed on three soil samples, and the following data were collected: Material weight of empty pycnometer weigt of dry soil weight of weight of pycnometer pycnometer Temperature + water +water+soil g Sand 1 106.6 Sand 2 106.6 Sand 3 106.6 2-a) Briefly describe the test procedure and discuss its applications in practice 2-b) The corrected specific gravity of SAND 1 G5,20 2-c) The corrected specific gravity of SAND 2 G5,20 2-d) The corrected specific gravity of SAND 3 G5,20 55.4 50 60 === === g 385.5 371 392 351 340 355 с 18 24 20

SEE MORE QUESTIONS

Recommended textbooks for you

Principles of Geotechnical Engineering (MindTap C…

Civil Engineering

ISBN:

9781305970939

Author:

Braja M. Das, Khaled Sobhan

Publisher:

Cengage Learning

Fundamentals of Geotechnical Engineering (MindTap…

Civil Engineering

ISBN:

9781305635180

Author:

Braja M. Das, Nagaratnam Sivakugan

Publisher:

Cengage Learning

Principles of Geotechnical Engineering (MindTap C…

Civil Engineering

ISBN:

9781305970939

Author:

Braja M. Das, Khaled Sobhan

Publisher:

Cengage Learning

Fundamentals of Geotechnical Engineering (MindTap…

Civil Engineering

ISBN:

9781305635180

Author:

Braja M. Das, Nagaratnam Sivakugan

Publisher:

Cengage Learning

SEE MORE TEXTBOOKS