A Sodium Chloride (0.1920g) NaCl was assayed using volhard Method, using 52mL of 0.0975N AGNO3 and 12.3 mL of 0.1192Ammonium thioscyanate. Calculate the sample in %.
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- Density of solution:Trial 1: 1.2 g/mLTrial 2: 1.2 g/mLTrial 3: 1.2 g/mL Average density = 1.2 g/mL What is the relative average deviaion, %?Q3/ A) 0.63 g of a sample containing Na CO,, NaHCO; and inert impurities is titrated with 0.2 M HCI, requiring 17.2 ml. to reach the phenolphthalein end point and a total of 43.5 mL to reach the modified methyl orange end point, How many grams Na CO, and NaHCO, are in the mixture?cium chloride per liter. Express the centration in terms of milliequivalents of calcium chloride (CaCl2-2H20-m.w 147) per liter. con- 27. How many milliequivalents/of potassium would be supplied daily by the usual dose (0.3 mL three times a day) of saturated potassium iodide solution? Saturated po- tassium iodide solution contains 100 g of potassium iodide per 100 mL.oluce 28. An intravenous solution calls for the addi- tion of 25 mEq of sodium bicarbonate. How many milli 4%
- Method used was Volhard Method Sample preparation: 5ml sample diluted in 100 ml. 20ml aliquot was used for analysis. Concentration of AgNO3: 0.0609M Calculate mass of NaCl and % NaCl (w/v)25mL 10% Na04 salution ? mmol theo mmoldikenzalacetone theo mass divemaaletone mass recovered 1 mmol 26g benzaldehyde. ? ML 2 mmol 7. 0.8mL acetone 2 mmolJiter of (9) Artout How many moles Naoh are present in 218mL of 1.5M Solution? □ in Ins în chemil disit (5) which of had the (1) 4 moke Solute dissolved im (ii) s the following greast Concentration ? (iii) (10) 5 liter at Solution moles at Solute dissolved in 0.5 liters of Solution 6 moled of Solete dissolved im 0.5 liters of Solution s mole of solute dissolved liters of solution îm GIVE EXPLAINED HANDWRITTEN ANSWER
- A 0.2182g sample of NaCl was assayed by the Volhard Method using 50mL of 0.0985N AgNO3 and 11.75mL of 0.1340N NH4SCN. Calculate the %NaCl in the sampleQ1) A Sada- Lime Sample is g0% NaoH and 10% Cao. f 3 gm is dissolved in 250 ml, what is Hthe tutal normality of the Selutton as abase ? How many mililiters of 0.5N H2S4 woutd be required to titrate ioo me of the Solution? Ans. ( 0.309N, 60.59 ml)A l.00ml aliquot of flsh ol was andyud for N using the Kieldahl methad : Afler chqastim, the dishlled ammania collected in l0omlof 0:0503M HCl. The excess HCl required 28.3 ml of o.124M NgoH for titatiun.Cale, the amound ot Nin the somple of fish oil as mglml
- A K2SO4 solution is prepared by weighing out a certain amount of the pure solid reagent,dissolving it to 500.0 mL in a volumetric flask. An aliquot was taken from this solution.of 25.00 ml and diluted to 500.0 ml. An aliquot of 5.00 was taken from this new solution anddiluted to 50.00 ml. A chemical analysis of this new solution showed a 0.100%(w/v)in K+. Calculate the weight of the pure solid K2SO4 used for the preparation of the original solution.and its concentration in each volumetric flask. The answer is 2.23x10^2gFive drops of dichlorofluorescein have been added to a solution containing 0.800 g sample which required 25.30 mL of 0.100 M AgNO3. (c) Calculate the weight percent NaCl in the original sample.Mass solute needed to prepare 0.500L of 0.2 M NaCO3 from a solid NaCO3 with a purity of 92.0wt%