A solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in the wire. d. Solution a) Let us first derive the expression for the tension. By Newton's First Law EF= the components of force that makes this so is EF -T Simplifying this results to T= g/ (0) Analyzing the figure above, we arrive at (4) = sqrt( 2. By substitution, we arrive at the following: T= +2 sqrt ( 2. )) If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal to 0.370 N

A solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in the wire. d. Solution a) Let us first derive the expression for the tension. By Newton's First Law EF= the components of force that makes this so is EF -T Simplifying this results to T= g/ (0) Analyzing the figure above, we arrive at (4) = sqrt( 2. By substitution, we arrive at the following: T= +2 sqrt ( 2. )) If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal to 0.370 N

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter12: Static Equilibrium And Elasticity

Section: Chapter Questions

Problem 64P: When using a pencil eraser, you exert a vertical force of 6.00N at a distance of 2.00cm from the...

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Problem A solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in the wire. L r m Solution a) Let us first derive the expression for the tension. By Newton's First Law ΣF 0 the components of force that makes this so is ΣFT cosphi mg = 0 Simplifying this results to T= m g/ cos Analyzing the figure above, we arrive at (4) = sqrt( L 2 + 2Lr %3D cos + | By substitution, we arrive at the following: T= m ( d + 2 L )g/( 2 sqrt ( L 2 + 2Lr If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal to T= 47 0.370 N
A solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in the wire. Solution a) Let us first derive the expression for the tension. By Newton's First Law ΣF = ______ the components of force that makes this so is ΣF = T ______ - ______ = 0 Simplifying this results to T = ______g/______(ϕ) Analyzing the figure above, we arrive at ______(ϕ) = sqrt( ______2 +______ ) / (______ /______ +______ ) By substitution, we arrive at the following: T = ______ ( ______ + 2 ______ ) g / ( ______ sqrt ( ______2 + ______ ) ) If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal to T = ______
QUESTION 5 Problem A solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in the wire. r m Solution a) Let us first derive the expression for the tension. By Newton's First Law ΣF0 the components of force that makes this so is
QUESTION 4 Problem A solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in the wire. d m Solution a) Let us first derive the expression for the tension. By Newton's First Law ΣΕ- the components of force that makes this so is EF = T = 0 Simplifying this results to T = g/ (4) Analyzing the figure above, we arrive at (4) = sqrt( 2+ + By substitution, we arrive at the following: T = + 2 )g/( sqrt 2+ If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal to T= 0.370 N
Problem A solid uniform ball with massm and diameter dis supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in the wire. L d Solution a) Let us first derive the expression for the tension. By Newton's First Law ΣF the components of force that makes this so is EF = T = 0 Simplifying this results to T= (4) Analyzing the figure above, we arrive at (4) = sqt 2+ By substitution, we arrive at the following: T= +2 sqrt ( )) If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal to T = 0.370 N
Problem A solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in the wire. r Solution a) Let us first derive the expression for the tension. By Newton's First Law
QUESTION 1 Problem A solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in the wire. Solution a) Let us first derive the expression for the tension. By Newton's First Law ΣF = ______ the components of force that makes this so is ΣF = T_____ -_____ = 0 Simplifying this results to T =________ g/_____(ϕ) Analyzing the figure above, we arrive at (ϕ) = sqrt(_____ 2 +______ ) / (_____ /_____ +_____ ) By substitution, we arrive at the following: T = (_____ + 2______ ) g / ( ______ sqrt (______ 2 +_____ ) ) If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal to T = ________ 0.370 N
A solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in the wire. a) Let us first derive the expression for the tension. By Newton's First Law ΣF = the components of force that makes this so is ΣF = T - = 0 Simplifying this results to T = g/(ϕ) Analyzing the figure above, we arrive at (ϕ) = sqrt( 2 + ) / ( / + ) By substitution, we arrive at the following: T = ( + 2 ) g / ( sqrt ( 2 + ) ) If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal to T = 0.370 N
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Problem A solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in the wire. d m Solution a) Let us first derive the expression for the tension. By Newton's First Law ΣF the components of force that makes this so is ΣF - T = 0 Simplifying this results to T = g/ (4) Analyzing the figure above, we arrive at (4) = sqrt( + By substitution, we arrive at the following: 2 T = + 2 )g/( sqrt ( )) If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal to T = 0.370 N
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