A solution of Tryptophan has an absorbance at 280 nm of 0.54 in a 0.5 cm length cuvette. Given the absorbance coefficient of trp is 6.4 x 103 Lmol-1cm-1. What is the concentration of solution?
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A solution of Tryptophan has an absorbance at 280 nm of 0.54 in a 0.5 cm length cuvette. Given the absorbance coefficient of trp is 6.4 x 103 Lmol-1cm-1. What is the concentration of solution?
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- The un-ionized form of the weak acid HA does not absorb in the visible region. When it ionizes, its conjugate base (A-) absorbs light strongly at 510 nm. The following data were obtained by measuring the absorbance at 510 nm of solutions with a concen- tration of 1.0 x 104 M HA in different pH buffers. pH Absorbance 2.0 0.00 3.0 0.00 4.0 0.00 5.0 0.025 6.0 0.180 7.0 0.480 8.0 0.570 9.0 0.595 10.0 0.595 11.0 0.595 12.0 0.595 What is the approximate pK of HA?If a solution of dissolved acid has pH = 2.5 and the pka for the acid chemical is 4.3 and you measure the concentration of the conjugate []-base to be 10mm, what is the concentration of the acid in the solution? pH = pka + logi [HA]Treatment of ammonia with phenol in the presence of hypochlorite yields indophenol, a blue product that absrobs light at 625 nm, which çan be used for the spectrophotometric determination of ammonia. gan OCF OH + NH3 indophenol anion To determinè the ammonia concentration in a sample of lake water, three samples are prepared. In sample A, 10.0 mL of lake water is mixed with 5 mL of phenol solution and 2 mL of sodium hypochlorite solution, and diluted to 25.0 mL in a volumetric flask. In sample B, 10.0 mL of lake water is mixed with 5 mL of phenol solution, 2 mL of sodium hypochlorite solution, and 2.50 mL of a 5.50 x 10-4 M ammonia solution, and diluted to 25.0 mL. Sample C is a reagent blank. It contains 10.0 mL of distilled water, 5 mL of phenol solution, and 2 mL of sodium hypochlorite solution, diluted to 25.0 mL. The absorbance of the three samples is then measured at 625 nm in a 1.00 cm cuvette. The results are shown in the table. Sample Absorbance (625 nm) A 0.361 B 0.608 C…
- A 1.43 x 10-4 L solution of 45.7 mg/mL protein was analyzed using the Kjeldahl procedure. After digestion of the protein, the liberated NH3 was collected in 9.80 mL of 0235 M HCl. The unreacted acid required 10.75 mL of a standard solution of 0.0149 M NaOH for complete titration. Calculate the weight percent of nitrogen in the protein. (Molar mass N = 14.00674 g/mol)The molar absorptivity constant of a particular chemical is 2.31 M/cm. Determine the concentration of a solution made from this chemical that has an absorbance of 0.408 with a cell path length of 1.12 cm.the total solubility of amoxicillin hydrate a weekly acid acidic drug with a PK of 7.11 in SO 00.0 1M in acquiesce buffered solution of a pH equaling 7.2 is
- The table below describes a procedure in preparing standard solutions of a protein sample with different concentrations. (A) Determine the concentrations of each tube if the starting concentration of the protein is 500 mg mL (B) Determine the equation of the line if the concentration (x-axis) was plotted vs the absorbance (y-axis). (C) What is the concentration, in mg mL, of the diluted unknown protein sample if the absorbance at 595 nm is 0.333? L-1. Tube Volume of protein, Volume of water, Final concentration, Absorbance #3 mL mL (at 595 nm) mg mL-1 0.00 5.00 0.113 12 0.70 4.30 0.184 3 1.40 3.60 0.251 14 2.10 2.90 0.329 15 2.80 2.20 0.385 3.50 1.50 0.454 17 4.20 0.80 0.503 8 5.00 0.00 0.577 Suppose that the unknown protein (diluted) sample in 4.C was diluted from a protein stock solution. Determine the concentration of the original unknown protein stock solution if 2.00 mL of the protein solution was mixed with 8.00 mL of water to create the unknown protein (diluted) sample in 4.C.In the preparation of the standard curve for protein analysis, 50 mn BSA (bovine serum albumin) dissolved in H2O to a final volume of 5 mL was used as stock solution. What is the weight of BSA in 0.1 mL of stock solution? In 0.2 mL?What is the concentration of a solution with an absorbance of 0.23 a.u. in ppm when y=45.3509y
- y = 3506.2x + 0.0421 R2 = 0.9978 A student prepared a solution that had 5.00 mL 0.002 M iron(III) nitrate in 1 M nitric acid, 3.00 mL 0.002 M potassium thiocyanate, and 2.00 mL DI water. Using the standard curve above, if the absorbance for the solution was 0.422, calculate the equilibrium constant, Keq.9bii and 11bWARIARTAM 2. 1.2589 g of a certain brand of milk powder required 25.89 mL of 0.01873M EDTA to titrate the calcium contained in the sample. (a) What is the percent calcium in the sample? (b) Would the true result be higher, lower, or not be affected if the milk powder sample has been slightly wet?