A steel bolt has a diameter of 8 mm. The bolt is encased by a bronze tube that has an outer diameter of 15 mm and inner diameter of 8 mm. A force is applied to the bolt. F d3 d1 F Values for the figure are given in the following table. Note the figure may not be to scale. Variable F₁ Value 25 kN Esteel 200 GPa Ebronze 105 GPa a. Determine the magnitude of the normal force in the steel bolt, Nsteel. b. Determine the magnitude of the normal force in the bronze tube, Nbronze. c. Determine the magnitude of the normal stress in the steel bolt, σ steel. d. Determine the magnitude of the normal stress in the bronze tube, Obronze. Round your final answers to 3 significant digits. N steel = KN Nbronze = KN σ steel = MPa Obronze = MPa

The two rods (A-B and B-C) shown in the left panel are connected by pins at A, B, and C. The cross sections of A-B and B-C are 10mm×13mm and 10mm×10mm, respectively. The bilinear stress-strain relation shown in the right panel is for the material used to make the two rods, where Ei is the slope of the stress-strain curve for stresses between 0 and 80 MPa and E2 is the slope for stresses larger than 80 MPa. Note that Hooke's law is only valid for stresses up to 80 MPa. A 1 1 B 0.900 m 3 P = 30 kN 2.44 m C σ MPa 80 E₂ = 40 GPa E₁ = 80 GPa E a) Given the conditions above, find the axial elongation for each rod when subjected to P=30KN. b) Find the final position of Point B due to the applied load P at that location. Hint: Assume point B moves by unknown amounts Ax and Ay from its initial position, and then use right triangles to write the known final lengths of the cables in terms of Ax and Ay. The equations can be simplified by assuming terms Ax² and Ay² are so small they can be…

Consider the frame in (Figure 1). The crate weighs 400 lb. Follow the sign convention. Figure 4 ft A B 1.5 ft 1.5 ft 1.5 ft 1.5 ft F /C . E 0 D 0.4 ft < 1 of 1 ▼ Part D Determine the normal force at point E. Express your answer in pounds to three significant figures. NE = Submit Part E VE = Submit Determine the shear force at point E. Express your answer in pounds to three significant figures. Part F [5] 195| ΑΣΦ | 11 | vec 4 Request Answer ME = Π| ΑΣΦ I Request Answer vec Determine the moment at point E. Express your answer in pound-feet to three significant figures. [V=| ΑΣΦ www. vec ? ? ? lb lb lb-ft

A steel pipe has an inside diameter of d = 250 mm and an outside diameter of D = 268 mm. The length of the pipe is L = 6.0 m. The changes in dimension caused by an increase in temperature of 80°C for the: Outside diameter - Blank 1 mm Inside diameter - Blank 2 mm Lenght - Blank 3 mm Note: All answer must be round off up to 3 decimal places.

Suppose that P₁ = 540 lb and P₂ = 720 lb. (Figure 1) Figure ▼ ♥ G Part A FBC = Submit Part B 48- FCF = Part C B P₁ -48- Determine the force in the member BC. Express your answer in pounds to three significant figures. Enter negative value in the case of compression and positive value in the case of tension. FFE = P₁ 15. ΑΣΦ 41 | vec Request Answer -4 ft 1. @ 1 of 1 1 vec 4 ft P₂ Determine the force in the member CF. Express your answer in pounds to three significant figures. Enter negative value in the case of compression and positive value in the case of tension. VAX 1 vec 1 → BINC ? Determine the force in the member FE. Express your answer in pounds to three significant figures. Enter negative value in the case of compression and positive value in the case of tension. IVE ΑΣΦ FE ? lb * ? lb lb

The shear stress-shear strain diagram for a material is shown. The bolt used to hold the lap joint is made of this material and has a diameter of 0.35 in. The material has a Poisson's Ratio of 0.2. T (ksi) F T1 G = Values for the figure are given in the following table. Note the figure may not be to scale. Variable T1 Y1 Value 40 ksi 0.003 rad 71 -7 (rad) a. Determine the Shear Modulus of the allow, G. b. Determine the Elastic Modulus of the allow, E. c. Determine the force required to cause the material to yield, F. Round your final answers to 3 significant digits/figures. ksi

Q1- The rigid bar of negligible weight is supported as shown in Fig- IS W- 80 kN, compute the temperature change of the assembly that will cause a tensile stress of 50 MPa in the steel rod. Use the following data: Bre Steel 15 m A (mm') a (/c°) 110m E (GPa) Steel rod 300 Bronze rod 1400 11.7* 10* 200 18.9 10 25m 83

Replace the loading by an equivalent resultant force. (Eigure 1) Suppose that wy -20 lb/ft, w₂=5 lb/ft, and F= 70 lb Figure 98 € 50 1 of 1 > Y Determine the magnitude of the resultant force Express your answer in pounds to three significant figures. FR= Submit Part B d= VG ΑΣΦ Submit Specify the location of the force on the beam, measured from A Express your answer in feet to three significant figures. Request Answer Ivec 195] ΑΣΦ IT Request Answer vec GWD ? ft ? lb

In the Figure 6, the absolute force value in the bar AB is (in kN): Figure 6: 5 m A 20 kN 5 m 5 m Im B الاختيارات 10.55 O 11.55 O 9.55 O 8.55 O

When a bar of 22 mm diameter is subjected to an axial pull of 60 kN the extension on the 49 mm gauge length is 0.1 mm and there is a decrease in diameter of 0.013 mm. Calculate the Young's Modulus. Provide your answer in GN/m2 to the nearest whole number.