Answered: A strong magnet is placed under a…

Physics for Scientists and Engineers with Modern Physics

10th Edition

ISBN:9781337553292

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter28: Magnetic Fields

Section: Chapter Questions

Problem 27P: A strong magnet is placed under a horizontal conducting ring of radius r that carries current I as...

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The problem is described in the attached image. It's regarding the calculation of the force due to a magnetic field over a conducting ring.

I can calculate most of the problem. The force is basically:

F = I * B * 2 * PI * R * SIN(X), where X is the angle between the magnetic field vector, and the vector with the direction of the electric current. Now, how do I calculate this angle? I've seen an answer that uses theta (provided by the exercise) as X, but why would theta be the angle between those two vectors, if it's only the angle between the magnetic vector and the vertical axis?

A strong magnet is placed under a horizontal conducting ring of
radius rthat carries current I as shown in Figure P28.27. If the
magnetic field B makes an angle 0 with the vertical at the ring's
location, what are (a) the magnitude and (b) the direction of the
resultant magnetic force on the ring?
Figure P28.27

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