A student determines that an aqueous solution that contains 0.484 M potassium fluoride and 0.325 M hydrofluoric acid, also has a H₂O concentration of 6.53x104 M. Based on these data, calculate the value of the equilibrium constant K for the equilibrium: HF(aq) + H₂0H₂0+ (aq) + F(aq) (1) as is usually done, without the inclusion of water in the expression for K: K= (2) for comparison, with the inclusion of water in the expression for K: K-

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Chapter12: Chemical Equilibrium
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Chemistry
A student determines that an aqueous solution that contains 0.484 M potassium fluoride and 0.325 M hydrofluoric
acid, also has a H30+ concentration of 6.53x10-4 M. Based on these data, calculate the value of the equilibrium
constant K for the equilibrium:
HF(aq) + H₂0H30+ (aq) + F(aq)
(1) as is usually done, without the inclusion of water in the expression for K: K=
(2) for comparison, with the inclusion of water in the expression for K: K=[
Transcribed Image Text:Chemistry A student determines that an aqueous solution that contains 0.484 M potassium fluoride and 0.325 M hydrofluoric acid, also has a H30+ concentration of 6.53x10-4 M. Based on these data, calculate the value of the equilibrium constant K for the equilibrium: HF(aq) + H₂0H30+ (aq) + F(aq) (1) as is usually done, without the inclusion of water in the expression for K: K= (2) for comparison, with the inclusion of water in the expression for K: K=[
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