a) The objective function, for the LP model = Minimize Z = 5X AB +8X AC +6 XAE + 0X BB +4 XBC Subject to: +12 XBE + 4XCB +0XCC +7XCE + 7X DB + 2X DC +5XDE + 12 XEB+7XEC+0XEE XAB+XAC +XAE = 750 X BB+X BC +X BE = 600 XCB+XCC +X CE = 150 XDB +XDC+X DE = 800 XEB +XEC +XEE = 500 XAB + XBB + XCB + XDB + X EB X AC + XBC + XCC + X DC + XEC A B number of students in sector number of students in sector number of students in sector number of students in sector C D number of students in sector E ≤1,000 school B capacity ≤1,000 school C capacity ХАЕ + ХВЕ For all X;; ≥0 + XCE + XDE + XEE ≤1,000 school E capacity non negativity condition b) Using a computer software for solving LP, the objective value at the optimal solution achieved is: Minimum number of total miles traveled (objective value) = (round your response to a whole number).

Practical Management Science
6th Edition
ISBN:9781337406659
Author:WINSTON, Wayne L.
Publisher:WINSTON, Wayne L.
Chapter2: Introduction To Spreadsheet Modeling
Section: Chapter Questions
Problem 20P: Julie James is opening a lemonade stand. She believes the fixed cost per week of running the stand...
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Question
a) The objective function, for the LP model =
Minimize Z =
5X AB +8X AC +6 XAE
+
0X BB +4 XBC
Subject to:
+12 XBE +
4XCB +0XCC +7XCE
+
7X DB + 2X DC +5XDE +
12 XEB+7XEC+0XEE
XAB+XAC +XAE
=
750
X BB+X BC +X BE = 600
XCB+XCC +X CE = 150
XDB +XDC+X DE = 800
XEB +XEC +XEE = 500
XAB + XBB + XCB + XDB + X EB
X AC + XBC + XCC + X DC + XEC
A
B
number of students in sector
number of students in sector
number of students in sector
number of students in sector
C
D
number of students in sector
E
≤1,000 school B capacity
≤1,000 school C capacity
ХАЕ + ХВЕ
For all X;; ≥0
+ XCE +
XDE + XEE
≤1,000 school E capacity
non negativity condition
b) Using a computer software for solving LP, the objective value at the optimal solution achieved is:
Minimum number of total miles traveled (objective value) =
(round your response to a whole number).
Transcribed Image Text:a) The objective function, for the LP model = Minimize Z = 5X AB +8X AC +6 XAE + 0X BB +4 XBC Subject to: +12 XBE + 4XCB +0XCC +7XCE + 7X DB + 2X DC +5XDE + 12 XEB+7XEC+0XEE XAB+XAC +XAE = 750 X BB+X BC +X BE = 600 XCB+XCC +X CE = 150 XDB +XDC+X DE = 800 XEB +XEC +XEE = 500 XAB + XBB + XCB + XDB + X EB X AC + XBC + XCC + X DC + XEC A B number of students in sector number of students in sector number of students in sector number of students in sector C D number of students in sector E ≤1,000 school B capacity ≤1,000 school C capacity ХАЕ + ХВЕ For all X;; ≥0 + XCE + XDE + XEE ≤1,000 school E capacity non negativity condition b) Using a computer software for solving LP, the objective value at the optimal solution achieved is: Minimum number of total miles traveled (objective value) = (round your response to a whole number).
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