A) The solid phase of a point (in the two-phase region) in the Bi-Sb alloy contains 75 at% of Sb.The fraction of the liquid phase of this point is approximately 0.37. From the figure, find thefollowing information of thispoint:650630.6 °C6001- The temperature.2- The overall alloy composition(C.).3- The composition of the liquidphase.4- The fraction of the solid phase.550Liquid9 500450400350300271.4 °Cα25020010100304050Atomic60708090Bipercent SbSbTemperature (°C)20

Given: The percentage of Sb = 75% The fraction of liquid = 0.37

Answered: A) The solid phase of a point (in the…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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(c) in the Cu and Ag phase diagram shown in Figure 1.1, consider an alloy composition of 40 wt% Cu - 60 wt% Ag. Composton Ca RD 20 1200 우 100 2200 2000 1000 pnbn- :000 1600 8.0 1400 912 :200 G00 Sous :000 400 G00 200 0 400 100 40 60 Composition rwts AD Figure 1.1: Cu - Ag Phase Diagram i. What Phases are present in the Alloy at 800° C? i. What are the compositions of present phases if the alloy is cooled by 20° C? iii. What are the mass fraction of phases? If the alloy was further cooled by 2° C, determine the volume fraction of the phases? Take the densities of Cu and Ag as 8.96 and 10.49 g/cm' respectively. iv.
For 40 wt% Sn – 60 wt% Pb alloy at 150 oC (at point B) as shown in Figure, i. State the name of phase(s) present. ii. Calculate the composition(s) of the phase(s) present. 600 300 Liquid 500 a+L 200 400 300 100 200 100 20 60 100 (Pb) (Sn) Composition (wt % Sn) Temperature ("C) Temperature ("F)
The figure below shows a hypothetical binary eutectic phase diagram on which we indicate an alloy composition of 27% B. Calculate the following quantities: a. Fraction of primary solid that forms under equilibrium cooling at eutectic temperature b. Fraction of liquid with the eutectic composition that will transform to two solid phases below the eutectic isotherm c. The amount of a and ß that will form from the liquid just below the eutectic isotherm. L+B L+a B 20 37 73 27 a +B
part a) A carbon-Fe alloy containing 1.5 wt% C is cooled down to 800°C. Determine what phases are present, the fraction of each phase present, and the composition of each phase. part b) A carbon-Fe alloy containing 1.5 wt% C is cooled down to 400 Celsius. Same as above, determine what phases are present, the fraction of each phase present, and the composition of each phase. use the picture below Irn-Iron Carbide Phase Diagram 1600 8 (Ferrite)N538°C 1100 2000 1495°C Liquid 1000- 1400 1394°C 1200 Y (austenite) 2500 y +liquid 1148°C 2.11% 900 Y+ Fe,C 4.30% 2000 1500 800 1000 Y+ cementite Detail view 727°C a+y 700 912°C 727°C a+y 80에 0.77% 0.022% 1500 Ferrite 600 600 a + cementite -Fe,C 1000 α (errte) 1000 Cementite (FeC) - 500 400 a + Fe,C 1 Carbon (% by weight) 6 6.67 0.5 1.0 Carbon (% by weight) 1.5 2.0 2.5 (a) (b) FIGURE 5.4 (a) The iron-iron carbide phase diagram. (b) Detailed view of the microstructures above and below the eutectoid temperature of 727°C (1341°F). Because of the…
Calculate the weight fraction for phases at point B? what are those phases? Is there any eutectic rection? How many phases are present in this diagram? Cu-Ni system T(°C) TA 1300 -L (liquid): A tie ļine liquidus L +a Тв EB solidus (solid) 1200 TD ID 20 3032 35: 4043 50 Ca wt% Ni
Temperature ("C) Temperature ($1 Consider 1 kg of Copper - Silver alloy (Cu - Ag) containing 75 wt% Ag. The phase diagram of the alloy is shown in the figure below. The alloy is cooled to 778 °C (just below the eutectic temperature). Calculate the mass in kg of the eutectic phase B (phase B that appears during the eutectic reaction) that forms? Composition (at% Ag 20 40 60 100 2200 80 1200 2000 Liquidus 1000 LIquid 1800 Solidus 1600 800 779°C (T 80 91.2 1400 IC. 1200 600 Solvus T000 400 800 200 20 40 80 100 (Cu) Composioon wt A
700 L 600 M a + L Mg, Pb 500 P 465 400 L Mg Pb 300 200 a + Mg Pb B+ Mg Pb 100 20 40 60 80 100 Mg Composition (wt% Pb) Pb Mg,Pb Using the above figure, sketch neatly the microstructure of the alloys (given in the below table) and determine the amount of each phase presented. Structure of the alloys at different compositions 田 Compositions &temperature 10%Pb,90%Mg Structure Structure Compositions &temperature 20%Pb, 80%Mg @400°C @0°C My.Pb 50%Pb,50%Mg 67%Pb, 33%Mg @0°C Mgz PB @0°C 81%Pb,19%Mg 90%Pb,10%Mg @200°C @0°C Temperature ("C)
KS) A binary alloy having 28 wt% Cu and balance Ag solidifies at 779°C. The solid consists of two phases a and B. Phase a has 9% Cu whereas phase ß has 8 % Ag at 779°C. At room temperature these are pure Ag and Cu respectively Sketch the phase diagram. Label all phases and temperatures. The melting points of copper and silver are 1083° and 96100 respectively us? Estimate the amount of a and B in the above alloy at 779°C and at room temperature.) b) Calculate the mass fraction of phases for 40% Cu alloy at 300 °C and TR c) What is the composition of the alloys in (b) following:
Is it possible to have a copper-nickel alloy that, at equilibrium, consists of a liquid phase of composition 20 wt% Ni-80 wt% Cu and also an a phase of composition 37 wt% Ni-63 wt% Cu? If so, what will be the approximate temperature of the alloy? If this is not possible, explain why. Temperature (°C) 1600 1500 1400 1300 1200 1100 1000 0 1085°C (Cu) 20 Liquid Liquidus line L B 40 a+L a A 60 Composition (wt% Ni) (a) 1455°C Solidus line 80 2800 2600 2400 2200 2000 100 (Ni) Temperature (°F) Temperature (°C) 1300 1200 20 Liquid Tie line. a + Liquid a 1 KR I 1 1 B ↑ Co a + Liquid -S 30 CL Composition (wt% Ni) (b) 40 1 Ca a 50
2) There is an aluminum-copper alloy. The phase diagram is given below. What heat treatment do you apply? Using this graph, how is it possible to increase the strength and hardness of this alloy? Consider this question within the scope of heat treatments. Composition (at % Cu) 10 20 30 700 1200 600 L a+ L 0 +L 1000 a 500 (CuAl,) a + 0 800 400 600 300 10 20 30 40 50 (AI) Composition (wt% Cu) Temperature (°C) Temperature (°F)
1-The microstructural design of Iron-Carbon(Fe-C) alloys has led to the development of vast range of steels for structural material applications. The phase diagram provide means for producing specific microstructures. Using the phase diagram below to answer the following questions A – If the liquid mixture of Fe-3%Wt C is slowly cooled from 1600 C to 1200C indicate the phase(S) that are present at 1200 C . Also calculate the composition of the of phases.(10) B-Describe the sequence of all phase transformation that accour from Fe-1.5%wt C is slowly cooled from 1600 C to 400 C. Use the diagram below to to describe the microstructures for each phase transformation (10)
In the binary phase diagram for the Cu-Ni system in the Figure provided: 1. Draw the microstructures for each point for the alloy upon cooling (A-E) and label ALL phases! 2. What are the compositions (C's) of EVERY phase and the relative phase amounts (W's) for each microstructure A-E? Show all work! T(°C) (liquid) L 20 (a, solid) 30 A BUD E 40 Co OOOOO w 10 50 wt% Ni CL= Ca= CL= Ca= CL= Ca= C₁= Cu= C₁= Ca= WL= Wa= WL= Wα= W₁= W= W₁= Wa= W₁= Wu= A B E

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