A three-step process for producing molten iron metal from Fe203 is: 1. 3FE203 + CO –→ 2FE304 + CO2 2. Fez04 + CO - 3FEO + CO, 3. Feo + CO → Fe + CO2 Assuming that the reactant cO is present in excess and that the yields, respectively, for the three steps are 81.9%, 65.9% and 60.5%, what mass of iron metal would be produced from 360. kg of Fe,03?

Introductory Chemistry: A Foundation
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Problem 20QAP: Consider the iron alloy described in Question 19. Suppose it is desired to prepare 1.00 kg of this...
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A three-step process for producing molten iron metal from Fe203 is:
1. ЗFe203 + со — 2Fe3О4 + CO2
2. Fe304 + CO— ЗFeО + CO2
3. Feo + CO → Fe + CO2
Assuming that the reactant CO is present in excess and that the yields, respectively, for the three steps are 81.9%, 65.9% and 60.5%, what mass of iron metal would be produced from 360. kg of Fe,03?
Transcribed Image Text:A three-step process for producing molten iron metal from Fe203 is: 1. ЗFe203 + со — 2Fe3О4 + CO2 2. Fe304 + CO— ЗFeО + CO2 3. Feo + CO → Fe + CO2 Assuming that the reactant CO is present in excess and that the yields, respectively, for the three steps are 81.9%, 65.9% and 60.5%, what mass of iron metal would be produced from 360. kg of Fe,03?
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