A uniform electric field points in the :-direction, E = Ek. By explicitly calculating the surface integral , E - dS, show that the flux of E through the surface s = {(1, y. -) € R* : +y² + ? = a°, z > 0} (as shown in the diagram), is given by Eza". Comment on why this is to be expected.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter6: The Trigonometric Functions
Section6.6: Additional Trigonometric Graphs
Problem 78E
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A uniform electric field points in the :-direction, E = Ek. By explicitly calculating the surface
integral f, E - dS, show that the flux of E through the surface
s = {(z, y. 2) € R* : =² +y² + =² = a°, z > 0}
(as shown in the diagram), is given by Eza". Comment on why this is to be expected.
Transcribed Image Text:A uniform electric field points in the :-direction, E = Ek. By explicitly calculating the surface integral f, E - dS, show that the flux of E through the surface s = {(z, y. 2) € R* : =² +y² + =² = a°, z > 0} (as shown in the diagram), is given by Eza". Comment on why this is to be expected.
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