a) Write a function to get the value of the Nu node in a Linked List. [Note: The first (N=1) item inthe list means the item at index 0.] It takes two parameters: the list or its head, and N. ReturnFalse if the list has fewer than N elements. The Linked List structure supports the followingfunction.def getlead(self):return selt.head # it points to a Node structureThe Node structure supports the following functions.def getData(self):return self.data # it returns the value stored in the Nodedef getNext(self):return self next # it points to the next Nodeb) Write a function that counts the number of times a given integer occurs in a Linked List.Assume similar structures as defined in 1.

Program: class Node: def __init__(self, data=None): self.data = data self.next = None def…

a) Write a function to get the value of the Në node in a Linked List. [Note: The first (N=1) item in the list means the item at index 0.] It takes two parameters: the list or its head, and N. Return False if the list has fewer than N elements. The Linked List structure supports the following function. det getlead(self): return self.head # it points to a Node structure The Node structure supports the following functions. def getData(self): retun self.data # it returns the value stored in the Node def getNext(self): return self.next # it points to the next Node b) Write a function that counts the number of times a given integer occurs in a Linked List. Assume similar structures as defined in 1.

a) Write a function to get the value of the Në node in a Linked List. [Note: The first (N=1) item in the list means the item at index 0.] It takes two parameters: the list or its head, and N. Return False if the list has fewer than N elements. The Linked List structure supports the following function. det getlead(self): return self.head # it points to a Node structure The Node structure supports the following functions. def getData(self): retun self.data # it returns the value stored in the Node def getNext(self): return self.next # it points to the next Node b) Write a function that counts the number of times a given integer occurs in a Linked List. Assume similar structures as defined in 1.

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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struct node{ int a; struct node * nextptr; }; Write two functions. One for inserting new values to a link list that uses the given node structure. void insert(struct node **head, int value); Second function is called to count the number of even numbers in the link list. It returns an integer that represents the number of even numbers. int countEvenNumbers(struct node *head); Write a C program that reads a number of integers from the user and insert those integers into a link list (use insert function). Later pass the head pointer of this link list to a function called countEvenNumbers. This function counts and returns the number of even numbers in the list. The returned value will be printed on the screen. Note 1: Do not modify the function prototypes. Sample Input1: Sample Output1: 45 23 44 12 37 98 33 35 -1 3 Sample Input2: Sample Output2: 11 33 44 21 22 99 123 122 124 77 -1 4
Multiple choice in data structures void doo(node<int>*root){ if(root !=0) { node<int>*p=root; while(root->next!=0) root=root->next; p->data=root->data; } What is this code do? a. swap the first item with the last item in the linked list b. set the first item in the linked list as the last item c. doesn't do anything because the root parameter is passed by value d. change the root item in the binary tree with the farthest leaf item
struct nodeType { int infoData; nodeType * next; }; nodeType *first; … and containing the values(see image) Using a loop to reach the end of the list, write a code segment that deletes all the nodes in the list. Ensure the code performs all memory ‘cleanup’ functions.
Don't copy from other websties a) Write a function to get the value of the Nthnode in a Linked List. [Note: The first (N=1) item in the list means the item at index 0.] It takes two parameters: the list or its head, and N. Return False if the list has fewer than N elements. The Linked List structure supports the following function. def getHead(self): return self.head # it points to a Node structure The Node structure supports the following functions. def getData(self): return self.data # it returns the value stored in the Node def getNext(self): return self.next # it points to the next Node b) Write a function that counts the number of times a given integer occurs in a Linked List. Assume similar structures as defined in 1.
C++ Programming Language ::::::: Redo the same functions this time as nonmember functions please : NOTE: You can add only one function into the linked list class get_at_position which will return value of element at given position. 1) Insert before tail : Insert a value into a simply linked list, such that it's location will be before tail. So if a list contains {1, 2, 3}, insert before tail value 9 is called, the list will become {1, 2, 9, 3}. 2) Insert before value : Insert a value into a simply linked list, such that it's location will be before a particular value. So if a list contains {1, 2, 3}, insert before 2 value 9 is called, the list will become {1, 9, 2, 3}. 3)Count common elements : Count common values between two simply linked lists.So if a list1 contains {1, 2, 3, 4, 5}, and list2 contains {1, 3, 4, 6}, number of common elements is 3. 4) Check if sorted : Check if elements of simply linked lists are sorted in ascending order or not.So if a list contains {1, 3, 7, 8, 9}…
struct remove_from_front_of_dll { // Function takes no parameters, removes the book at the front of a doubly // linked list, and returns nothing. void operator()(const Book& unused) { //// TO-DO (13) |||| // Write the lines of code to remove the book at the front of "my_dll", // // Remember, attempting to remove an element from an empty data structure is // a logic error. Include code to avoid that. ///// END-TO-DO (13) //// } std::list& my_dll; };
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card_t * moveCardBack (card t *head); The moveCardBack function will take the card in front of the pile and place it in the back. In coding terms, you are taking the head of the linked list and moving it to the end. The function has one parameter which is the head of the linked list. After moving the card to the back, the function returns the new head of the linked list.
@6 The Reference-based Linked Lists: Select all of the following statements that are true. options: As a singly linked list's node references both its predecessor and its successor, it is easily possible to traverse such a list in both directions. According to the terminology introduced in class, the head reference variable in a singly linked list object references the list's first node. According to the terminology introduced in class, in a doubly linked list, each node references both the head and tail node. In a double-ended singly linked list, the tail reference variable provides access to the entire list. In a circular linked list, the last node references the first node.
ASSUMING C LANGUAGE True or False: You can have the data portion of a Linked List be a Struct containing a Linked List itself
struct Node { int data; Node * next; }; Node • head; a. Write a function named addNode that takes in a variable of type int and inserts it at the head of the list. b. Write a function named removeNode that removes a node at the head of the list.
find_last(my_list, x): Takes two inputs: the first being a list and the second being any type. Returns the index of the last element of the list which is equal to the second input; if it cannot be found, returns None instead. >>> find_last(['a', 'b', 'b', 'a'], 'b') 2 >>> ind = find_last(['a', 'b', 'b', 'a'], 'c') >>> print(ind) None • find_first(my_list, x): Takes two inputs: the first being a list and the second being any type. Returns the index of the first element of the list which is equal to the second input; if it cannot be found, returns None instead. >>> find_first(['a', 'b', 'b', 'a'], 'b') 1 >>> ind = find_first(['a', 'b', 'b', 'a'], 'c') >>> print(ind) None In python