a. For the following unbalanced equation, calculate how many grams of each product would be produced by complete reaction of 6.20 g of H₂. Indicate clearly the mole ratio used for the conversion. TiBr4 (9) + H₂(g) → Ti(s) + HBr(g) g Ti 9 HBr

Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter3: Chemical Reactions
Section3.2: Balancing Chemical Equations
Problem 3.1CYU: (a) Butane gas, C4H10, can burn completely in air [use O2(g) as the other reactant] to give carbon...
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a. For the following unbalanced equation, calculate how many grams of each product would be produced by complete reaction of 6.20 g of H₂. Indicate clearly the mole ratio used for the conversion.
TiBr4 (9) + H₂(g) → Ti(s) + HBr(g)
9 Ti
g HBr
b. For the following unbalanced equation, calculate how many grams of each product would be produced by complete reaction of 33.3 g of SiH4. Indicate clearly the mole ratio used for the conversion.
SiH4 (9) + NH3(g) → Si3 N4 (s) + H₂ (9)
g Si3 N4
g H₂
c. For the following unbalanced equation, calculate how many grams of each product would be produced by complete reaction of 87.0 g of H₂. Indicate clearly the mole ratio used for the conversion.
NO(g) + H₂(g) → N₂ (g) + H₂O(1)
g N₂
g H₂O
Transcribed Image Text:a. For the following unbalanced equation, calculate how many grams of each product would be produced by complete reaction of 6.20 g of H₂. Indicate clearly the mole ratio used for the conversion. TiBr4 (9) + H₂(g) → Ti(s) + HBr(g) 9 Ti g HBr b. For the following unbalanced equation, calculate how many grams of each product would be produced by complete reaction of 33.3 g of SiH4. Indicate clearly the mole ratio used for the conversion. SiH4 (9) + NH3(g) → Si3 N4 (s) + H₂ (9) g Si3 N4 g H₂ c. For the following unbalanced equation, calculate how many grams of each product would be produced by complete reaction of 87.0 g of H₂. Indicate clearly the mole ratio used for the conversion. NO(g) + H₂(g) → N₂ (g) + H₂O(1) g N₂ g H₂O
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