a. Given the result of a crosses below: Tall plant and short plant and Tall plant and Purple flower short plant and white flower white-flower purple flower 3a. 55 47 45 53 3b. 74 87 19 20 Determine the possible genotypes of the parent pea plants involved. Tall (S) is dominant t short (s) and Purple (W) is dominant to white (w) a = b=
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- More Crosses with Pea Plants: The Principle of Independent Assortment Consider the following cross: P1: AABBCCDDEE aabbccddee F1: AaBbCcDdEe (self-cross to get F2) What is the chance of getting an AaBBccDdee individual in the F2 generation?A. Consider this cross before answering the following questions: A pea plant heterozygous for the first trait and recessive for the second trait is crossed with a pea plant heterozygous for the first trait and homozygous-dominant for the second trait. 1. If there is complete dominance in the expression of the two traits, what is the probability that the F1 progeny will be a. heterozygous for the first trait? b. expressing the dominant feature of the first trait? c. heterozygous for both first and second traits? d. expressing recessive feature of the second trait? e. recessive for both traits 2. It there is incomplete dominance in the expression of the two traits, what is the probability that the F1 progeny will be a. expressing the dominant feature for the second trait? b. expressing the dominant feature for both traits? c. expressing the dominant feature for the first trait and recessive feature for the second? d. expressing recessive feature for the first trait? e.…ibri 12 BIU A - A 4. 11. Mendel crossed peas having round seeds and yellow cotyledons with peas having wrinkled seeds and green cotyledons. All the F1 plants had round seeds with yellow cotyledons. a. What are the genotypes of the parent plants? b. What gametes could be produced by the parent with round seeds and yellow cotyledons? C. What gametes could be produced by the parent with wrinkled seeds and green cotyledons? d. What is the genotype of the F1 plants? e. What gametes could be produced by the F1 plants? hp
- A. Consider this cross before answering the following questions:A pea plant heterozygous for the first trait and recessive for the second trait is crossed with a pea plant heterozygous for the first trait and homozygous-dominant for the second trait. 1. It there is incomplete dominance in the expression of the two traits, what is the probability that the F1 progeny will be a. expressing the dominant feature for the second trait?b. expressing the dominant feature for both traits?c. expressing the dominant feature for the first trait and recessive feature for the second?d. expressing recessive feature for the first trait?e. expressing recessive feature for both traits?Punnett Squares Practice Monohybrid Crosses DIRECTIONS: All these genetic probiems deal with pea plants and heir traits. Use the following kay for ail problems. Put the gametes for the 1st parent of each cross along the top, and the gametes for the 2nd parent along the left side. T= Tall ( = Short S= Smooth Seed = Wrinkled Seed G= Green Pod Y= Yellow Seed P= Purple Flower g= Yellow Pod 2. TT x TE y- Green Seed A= White Flower 1. PP x PA 3. Sa x Sa 4. yy x yy 5. Gg x Gg PP PA AP YY Yy 99 GG Gg gg SS Sa sa 8. heterozygous yellow seed x green seed TT TE 6. hybrid tall x short Te x t 7. purebrid tall x short TT x 9. hybrid green pod x hybrid green pod 10. hybrid tall x purebred tall YY Yy 99 13. heterozygous purple flowers x TT T TT TE GG Gg gg TT Te 11. purebred purple flowers x white flowers 12. hybrid purple flowers x white flowers 14. hybrid smooth seeds x hybrid smooth seeds 15. short plant x short plant white flowers PP PA AP PP PA AA phenotype ratios: PP PA AE Ss Se TT TE Purple…a. In a type of plant, pink flowers (P) is dominant over white flowers (p), and tall (T) is dominant over short (t). Determine the genotypes of the parents in the following cross: Pink, tall x pink, short O / pink, tall: /s pink, short: /s white, tall: / white, short Genotypes: () (ii) Phenotypes: Pink, tall Pink, short b. A woman has blood type A MM. She has a child with blood type O MN. Which of the following men could not be the child's father? Explain your reasoning. Man Blood type Peter O NN Rob AB MN Doug B MN Simon A NN Mike АВ М
- picture shows the results of a cross between a tall pea plant and a short pea plant. Q. What phenotypes and proportions will be produced if a tall F1 plant is backcrossed to the tall parent?picture shows the results of a cross between a tall pea plant and a short pea plant. Q. What phenotypes and proportions will be produced if a tall F1 plant is backcrossed to the short parent?a. 1 dominant allele will contribute 120/10 = 12 cm to the base height of the plant.b. The height of the parent plant 1 Genotype of the parent plant 1 – D1D1D2D2D3D3d4d4d5d5 The height of the parent plant 2 Genotype of the parent plant 2 – d1d1d2d2d3d3D4D4D5D5Contributing alleles – D4D4D5D5. The height of the plant without any contributing alleles would be 80 cm. The plant with genotype d1d1d2d2d3d3D4D4D5D5 has 4 contributing allele each of which contributes 12 cm to the base. Hence, the height of the plant with genotype d1d1d2d2d3d3D4D4D5D5 would be 80 + 12 + 12 + 12 + 12 = 128 cm. c. Parents – D1D1D2D2D3D3d4d4d5d5 × d1d1d2d2d3d3D4D4D5D5 Gametes – D1D2D3d4d5 × d1d2d3D4D5 F1 generation – D1d1D2d2D3d3D4d4D5d5 The height of the plants of F1 generation = 80 + 12 + 12 + 12 + 12 + 12 = 140 cm Hence, Genotype of the F1 = D1d1D2d2D3d3D4d4D5d5 Phenotype of…
- 1. Complete the Punnett square for a cross between a homozygous red-flowered snapdragon (RR) and a homozygous white-flowered snapdragon (WW). Give the ratio for the phenotype and the genotype. Key F1 Genotypic Ratio: RR – red Phenotypic Ratio: wW- white RW- pink 2. Complete the Punnett Square for a cross between two Fi plants (WW). Give the phenotypic ratio for the F2 generation. F2 Phenotypic ratio: 3. Cite some possible applications of genetics to plant breeding.Introduction: A dihybrid cross is a cross between individuals that involves two pairs of contrasting traits. To Predict the results of a dihybrid, cross all possible combinations of the four alleles from each parent must be considered. You will examine a dihybrid cross involving both color and texture. Purple (P), is dominate to yellow (p), and smooth texture (S) is dominant to wrinkled (s). Both parent plants are heterozygous for both traits. Review genetics and the use of Punnett squares in a biology text before doing this experiment.MATERIALS: Assume you have ear of Corn. You need a heterozygous X heterozygous 9:3:3:1, purple/yellow, starchy/sweet. PROCEDURE: From above please write out: The crop The parental (P) cross phenotype, genotype, gametes Cross between two F1 Selfed testcross 1. First let us use a Punnett square to examine the theoretical outcome of the Heterozygous X Heterozygous dihybrid cross. USE a Punnett square. REMEMBER: a phenotype is how the offspring will…Make sure to include (genotypic ratios) For part A) make sure to have table or the phenotypic or genotypic ratios 5. In garden peas, green pod (P) is dominant to yellow pod (p) and tall stemmed (T) plants are dominant to short stemmed plants (t). Please give the genotypic and phenotypic ratios from the following crosses. a) Homozygous green pod homozygous tall stemmed plant crossed with a yellow pod (homozygous) short stemmed (homozygous) plant. b) Homozygous green pod homozygous tall stemmed plant crossed with a heterozygous green pod heterozygous tall stemmed plant. c) Heterozygous green pod heterozygous tall stemmed plant crossed with a heterozygous green pod heterozygous tall stemmed plant. d) Heterozygous green pod homozygous tall stemmed plant crossed with a yellow pod (homozygous) homozygous tall stemmed plant. These are dihybrid crosses. 7. In pea plants, flower colour and pollen shape are located on the same chromosome. A plant with purple flowers and…