A.find ig B. Then use current divison to find io 19-7 152 212 361 312-AL 40 in Series 1254+ 5·20=100/25=452 13-2 50. 452+62-1052 Resistance with ig=2 125V/102 = 19=12.5amps Current divison rule for io чол 10 = 19/A) = 12.5 (401) =10amps loamps (.24) = 2.4amps A-12.5amps B-2.4amps
A.find ig B. Then use current divison to find io 19-7 152 212 361 312-AL 40 in Series 1254+ 5·20=100/25=452 13-2 50. 452+62-1052 Resistance with ig=2 125V/102 = 19=12.5amps Current divison rule for io чол 10 = 19/A) = 12.5 (401) =10amps loamps (.24) = 2.4amps A-12.5amps B-2.4amps
Chapter29: Automatic Starters For Star-delta Motors
Section: Chapter Questions
Problem 4SQ: The closed transition contactor is energized only on transfer from star to delta. How is this...
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I need help to make sure, I need to find ig and then use current division to find io did I do it correctly?
Transcribed Image Text:A.find ig
B. Then use current divison to find io
19-7 152
212
361 312-AL
40 in Series
1254+
5·20=100/25=452
13-2
50.
452+62-1052
Resistance with ig=2
125V/102 = 19=12.5amps
Current divison rule for io
чол
10 = 19/A) = 12.5 (401)
=10amps
loamps (.24)
= 2.4amps
A-12.5amps
B-2.4amps
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