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Acetic Acid: Ka = 1.7 x 10-5 Hydrofluoric Acid: Ka = 6.8 x 104 Propionic Acid: Ka = 1.3 x 10-5 A 20.0 mL sample of 0.120 M propionic acid was titrated by 0.150 M NaOH. Calculate the pH at the following points. a) Before titration. b) After the addition of 10.0 mL of the base. c) At the equivalence point. d) After the addition of a total of 30.0 mL of the base

Acetic Acid: Ka = 1.7 x 10-5 Hydrofluoric Acid: Ka = 6.8 x 104 Propionic Acid: Ka = 1.3 x 10-5 A 20.0 mL sample of 0.120 M propionic acid was titrated by 0.150 M NaOH. Calculate the pH at the following points. a) Before titration. b) After the addition of 10.0 mL of the base. c) At the equivalence point. d) After the addition of a total of 30.0 mL of the base

Chemistry: The Molecular Science
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter15: Additional Aqueous Equilibria
Section: Chapter Questions
Problem 31QRT
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Acetic Acid: Ka = 1.7 x 10-5 Hydrofluoric Acid: Ka = 6.8 x 104 Propionic Acid: Ka = 1.3 x 10-5 A 20.0 mL sample of 0.120 M propionic acid was titrated by 0.150 M NaOH. Calculate the pH at the following points. a) Before titration. b) After the addition of 10.0 mL of the base. c) At the equivalence point. d) After the addition of a total of 30.0 mL of the base
Transcribed Image Text:Acetic Acid: Ka = 1.7 x 10-5 Hydrofluoric Acid: Ka = 6.8 x 104 Propionic Acid: Ka = 1.3 x 10-5 A 20.0 mL sample of 0.120 M propionic acid was titrated by 0.150 M NaOH. Calculate the pH at the following points. a) Before titration. b) After the addition of 10.0 mL of the base. c) At the equivalence point. d) After the addition of a total of 30.0 mL of the base
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