alcohol 9.17 mas isopropyl alcohol + 16.67 mois water d) What is the molarity of rubbing alcohol? (Assume isopropyl alcohol to be the solute) 0.35 e) What is the molality of the solution? f) What is the %m/m of this solution?

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter13: The Chemistry Of Solutes And Solutions
Section: Chapter Questions
Problem 107QRT
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d,e,f,g
9.17
25.84
5. Rubbing alcohols chemical component is isopropyl alcohol, C3HBO which has a density of 786
kg/m³. You should know the density of water g/mL). Rubbing alcohol can be purchased in
bottles at a 70% V/V concentration. Assuming 1.00 L of rubbing alcohol where C3H8O is the
solute:
= density
a) What is the density of isopropyl alcohol in g/mL?
786 x 10009
1000000 cm3
= 0.786 g/cm³ = 0.786 g/m²
b) How many moles of isopropyl alcohol and water are there?
IL=1000 mL
moi alcohol
weight
Volume
20
1000ml x 100 ml = 700ml
550.29 mol
1609
700mlx 0.786g/ml = 550.29
Water Present=(1000-700) = 300 m 1
Imer Water
300g|189.
9.17
300g 1md-1667 16.67 mol H₂O
mol C3H₂O
300 ml x 1g/ml = 300 g
c) What is the mole fraction of isopropyl alcohol in the rubbing alcohol?
mois isopropyl alcohol
mois isopropyl alcohol + mois water
e) What is the molality of the solution?
f) What is the %m/m of this solution?
0.786 g/m2
weight (g)
(mw (g/mol)
= 9.17 mc15
9.17 mois isopropyl alconal
9.17 mas isopropyl alcohol + 16.67 mois water
= 0.35487616
0.35
d) What is the molarity of rubbing alcohol? (Assume isopropyl alcohol to be the solute)
g) What is the concentration of isopropyl alcohol in ppm by mass?
Transcribed Image Text:9.17 25.84 5. Rubbing alcohols chemical component is isopropyl alcohol, C3HBO which has a density of 786 kg/m³. You should know the density of water g/mL). Rubbing alcohol can be purchased in bottles at a 70% V/V concentration. Assuming 1.00 L of rubbing alcohol where C3H8O is the solute: = density a) What is the density of isopropyl alcohol in g/mL? 786 x 10009 1000000 cm3 = 0.786 g/cm³ = 0.786 g/m² b) How many moles of isopropyl alcohol and water are there? IL=1000 mL moi alcohol weight Volume 20 1000ml x 100 ml = 700ml 550.29 mol 1609 700mlx 0.786g/ml = 550.29 Water Present=(1000-700) = 300 m 1 Imer Water 300g|189. 9.17 300g 1md-1667 16.67 mol H₂O mol C3H₂O 300 ml x 1g/ml = 300 g c) What is the mole fraction of isopropyl alcohol in the rubbing alcohol? mois isopropyl alcohol mois isopropyl alcohol + mois water e) What is the molality of the solution? f) What is the %m/m of this solution? 0.786 g/m2 weight (g) (mw (g/mol) = 9.17 mc15 9.17 mois isopropyl alconal 9.17 mas isopropyl alcohol + 16.67 mois water = 0.35487616 0.35 d) What is the molarity of rubbing alcohol? (Assume isopropyl alcohol to be the solute) g) What is the concentration of isopropyl alcohol in ppm by mass?
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