Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s) + 3Cl2(g) 2AlCl3 (s) You are given 25.0 g of aluminum and 30.0 g of chlorine gas ▾ Part A If you had excess chlorine, how many moles of of aluminum chloride could be produced from 25.0 g of aluminum?

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Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction:
2Al(s) + 3Cl2 (g)→2AlCl3 (s)
You are given 25.0 g of aluminum and 30.0 g of chlorine gas
Part A
If you had excess chlorine, how many moles of of aluminum chloride could be produced from 25.0 g of
aluminum?
Express your answer to three significant figures and include the appropriate units.
View Available Hint(s)
1.11
μA
→
g
JQ
PALL
?
Transcribed Image Text:Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s) + 3Cl2 (g)→2AlCl3 (s) You are given 25.0 g of aluminum and 30.0 g of chlorine gas Part A If you had excess chlorine, how many moles of of aluminum chloride could be produced from 25.0 g of aluminum? Express your answer to three significant figures and include the appropriate units. View Available Hint(s) 1.11 μA → g JQ PALL ?
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