AMPLIFIER'S FREQUENCY RESPONSE 4 Amplifier's Frequency ResponseVcc=20VR1 = 40 kohmR2 = 10 kohmRc = 4 kohmRE=2 kohmRs = 1 kohmRL = 2.2 kohmCs = 10 uFCc = 1 uFCE=20 uFCbc = 4 pFCbe = 36 pFCce 1 pFCwi = 6 pFCwo = 8 pFBeta = 100Rs+V₂2C5H+R₁VccR₂ Cw₁CbcRcСьеRECcCceCalculate the cutoff frequency due to Cc.a.10.2 Hzb.15.1 HzC.19.23 Hzd. 25.68 HzCECWo4●●●RL

Answered: Image /qna-images/answer/5122d277-d060-40ed-a20b-cc8638732350.jpg

Answered: Amplifier's Frequency Response Vcc=20V…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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We examined the common source amplifier shown in the figure in the 5th experiment. The selection criterion of the input capacitance is Xcin = 0.1Rin: Calculate the required input capacitance value, Cin , if an input signal with a frequency of 2 kHz is applied. Şekitde gösterilen ortak source yükseltecini 5. deneyde incelemiştik Giriş kapasitesinin seçim kriteri Xcin - 0.1Rin dir. 2 kHzlik giriç sinyali için gerektt tapasite, Cm değerini hesaplayınız. Circuit parameters / Devre Parametreleri R1 = 53 k2, R, = 17 k2 R1 RD Cout Vout D VDD M2 Cin G Vin R2 RS cs O a. 74.19 nF O b. 86.55 nF O c. 49.46 nF O d. 61.82 nF O e. 43.28 nF
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