An excavation of 10 m in soft clay is shown in the figure.Assuming the last level of strut is at GL-7.0 m, calculate thefactor of safety against inward yielding using the given soilproperties.10.0mGL-7.0m10.0m5.0m9s 15 kPaSoft clay 1:Yt=20 kN/m³C=30kPaQu=0°0.5m.-Silty clay 2:Yt=20 kN/m³C₁₁=90kPaQu=0°Bed Rock

Answered: An excavation of 10 m in soft clay is…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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A consolidated-drained triaxial test was conducted on a normally consolidated clay. Theresults are, Ϭ3 = 300 kN/m2, (ΔϬd)f = 250 kN/m2. Determine? Draw a neat Mohr Circle to aconvenient scale and determine following?a. Angle of friction ϕ’?b. Derive a relation between angle Ѳ (that the failure plane makes with the majorprincipal plane) and internal friction angle of soil (ϕ’)? Also find out the failure planeangle (Ѳ) in this case?c. Find the normal stress Ϭ’ and the shear stress Ƭ on the failure plane?d. Determine the effective normal stress on the plane of maximum shear stress andorientation of this plane?e. Determine the orientation of both major and minor principal planes?
Q1 The lower sand layer in the soil profile shown below is in an artesian condition. Calculate: 2 a) The effective stress () at the top and base of the clay layer. b) The height of water in the piezometer for = 0 at the base of the clay layer. > c) The maximum depth (Z) of the proposed excavation (Figure Q1 (b)). (Assume Z>2 m). 2.0 m 2.0 m 4.0 m Sand Tary' Ground water table Sand Clay Sand 4.0 m - 16.6 kN/m³ Ys20.6 kN/m³ You 20.6 kN/m² You 20.5 kN/m³ Figure Q1 (a) Sand Clay Sand Z Figure Q1 (b) W.T.
A soil profile is shown in the following figure. A new footing will be placed on the ground and the average vertical stress increment at the midpoint of the clay layer due to the new footing will be Ao, = 25.5 kPa. Estimate the final primary consolidation settlement of the clay layer. Assume that the clay is normally consolidated. New footing 2.8 m Ydry 18.0 kN/m³ W.T. 4.2 m Ywet = 18.6 kN/m³ 3.0 m = Ywet 18.2 kN/m³, e₁= 0.82 LL = 44, PL = 20 Sand Sand Clay Sand
2 m 2 m 3 m Figure P2.11 A Dry sand; e = 0.5 G, = 2.65 B Water table Sand Gs = 2.65 e = 0.6 C Clay w = 36% GS = 2.75 D Rock
5 The compression curve (void ratio, e vs. effective stress, o) for a certain clayey soil is a straight line in a semi-logarithmic plot and it passes through the points (e = 1.2; o = 50 kPa) and (e=0.6; o = 800 kPa). The compression index (up to two decimal places) of the soil is 100
An excavation of 10 m in soft clay is shown in the figure. Assuming the last level of strut is at GL-7.0 m, calculate the factor of safety against inward yielding using the given soil properties. 10.0m GL-7.0m 10.0m 5.0m 0.5m. 9s 15 kPa Soft clay 1: Yt=20 kN/m³ Cu=30kPa Qu=0° Silty clay 2: Yt=20 kN/m³ C₁ =90kPa Qu=0° Bed Rock
5. Saturated silty clay encountered in a deep excavation is found to have a water content of 28%. Determine unit weight of the clay in kN/m3. Assume Gs=2.7
Shear Strength of Soil The following are the results of two consolidated-drained triaxial tests on a clay: Test I: 03 = 140 kN /m²; 0,(railure) = 368 kN /m² Test II: 03 = 286 kN /m²; 0,(falare) = 701 kN/m² Determine the shear strength parameters; that is, c' and '. (Enter your answers to three significant figures.) kN /m? 3.
The compression curve (void ratio, e for a certain vs. effective stress, clayey soil is a straight line in a semi-logarithmic plot and it passes (e = 1.2; = 50kPa) through the points (e = 1.2; 0) V and (e=0.6;=800kPa). The compression index (up to two decimal places) of the soil is
A soil formation is composed of 5 m thick clay and 5 m thick sand being the sand above the clay. The ground water table (GWT) is located at 2 m below the ground surface. 40 kPa 2 m Sand Ydry = 17.66 kN/m^3 VGWT Sand 3 m Y sat = 20.93 kN/m^3 LI = 64% PL = 20% w = 40% 5 m Clay eo = 0.60 G. = 2.60 1. Calculate the primary compression index. [ Select ] 2. Calculate the primary consolidation settlement of the normally consolidated clay layer if there is a surcharge of 40 kPa acting on the ground surface. [ Select] 3. Calculate the secondary settlement of the clay layer 5 years after the completion of the primary consolidation settlement. Time for completion of primary settlement is 2 years. Use C, = 0.02. [Select ]
A footing of size 2m×2m transferring a pressure of 200 kN/m², is placed at a depth of 1.5 m below the ground as shown in the figure (not drawn to the scale). The clay stratum is normally consolidated. The clay has specific gravity of 2.65 and compression index of 0.3. 1.5m 1m 1.5 m 200 kN/m² Silty sand Clay Ya =15kN/m³ Y sat = 18kN/m³ Y sat = 17 kN/m³ GWT $0.5 m Dense sand Considering 2:1 (vertical to horizontal) method of load distribution and Y₁ = 10kN/m³, the primary consolida- tion settlement (in mm, round off to two decimal places) of the clay stratum is
During a subsoil exploration program, undisturbed normally consolidated silty clay samples were collected in Shelby tubes from location A as shown in Figure below 2 m G.W.T Silty sand e = 0.72; G, = 2.69 2.2 m 3.5 m Silty clay w = 22%; G, = 2.72 5.25 m Poorly graded sand = 19.8 kN/m³ 2.6 m Ysat Following are the results of four drained, direct shear tests conducted on the

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