ANSWER ASAP PLEASE The Ca2+ in a 25.00mL of underground powder was titrated with 28.60 mL of 0.01350 M EDTA. Calculate the concentration of Ca2+ in ppm. Round off your final answer to four significant figures.
Q: 4. Calcium in a 200-ul serum sample is titrated with 1.87 x 10-4 M EDTA solution, requiring 2.74 mL.…
A: Calcium is reactive element which is reacts with the EDTA chemical and form complex compound .The…
Q: Question 7 A student performed three DCM layer titrations in Part 2 and they reported the following…
A:
Q: Trial 1 Trial 2 Volume analyte (mL) 52.8 54.68 Volume titrant, final (mL) 14.68 14.55 Volume…
A: Given: Volume of analyte(citric acid) is 54.68 mL. The volume of titrant(NaOH) is 14.04…
Q: An EDTA solution was prepared by dissolving the disodium salt in 1 L of water. It was standardized…
A: Mass of CaCO3 = 0.5063 gMolecular mass of CaCO3 = 100.08 gmol
Q: QUESTION 2 Titration of a 100.0 mL aliquot of deep well water sample for total hardness requires…
A: Given that - Volume of water sample of deep well water = 100.0 mL Volume of EDTA used = 28.90 mL…
Q: Calculate the total concentration of ions( Na+ and Cl-) in a solution prepared by diluting 10mL of…
A: Using the formula , M1V1 = M2V2 Where M1 is the molarity of Na+ or Cl- ions in the stock solution…
Q: What is the maximum metallic concentration in 100.0 liters of water from a metallic hydroxide with a…
A:
Q: In the titration of 25.00 mL of a water sample, it took 19.040 mL of 4.965x 10−3 M EDTA solution to…
A: EDTA is used to measure the hardness of water Water hardness is primarily due to calcium and…
Q: 10. Find the pSr of a 50 ml solution of 0.1 M Sr* at pH 10, after addition of 0, 20, 50, and 100 ml…
A: Solution -
Q: Suppose Missy bon bon have 20.3 L sample of gas that contains an impurity, CO. The sample was then…
A:
Q: find the total hardness for water of lake contains (9.83 x10* ( m) of hco3, (1.25x 10 m) of…
A: Solution - According to the question - Given - The hardness of water is the sum of the…
Q: Titration Results Initial buret reading (ml) Final buret reading (ml) Total volume used (mL) 0.00…
A: Answer: This is question based on titration of strong acid against strong base where acid is the…
Q: Hd 14 12 10 00 5 4 2 0 0 Titration Data 0.5ml Volume (ml) 1.0ml 2ml
A:
Q: A 100 mL of 0.125 M CH₂COOH solution was shaken with 1.2 g charcoal for 5 min. After filtration, 10…
A: I have given a detailed solution for the problem as follows:
Q: Question 4. New December 18, 2020. The nitrite in a series of standard solutions (mg/L, n = 5) are…
A: Absorbance is the fraction of intensity of light that is absorbed by a material . According to…
Q: Pls compute how to prepare the following solutions: 1. 500.0 mL 0.1000 M stock EDTA solution a.…
A: The procedure to prepare the solutions is already provided. The amount of each of the substances to…
Q: Experiment 2. Impact of dilution on pH 1. For each of the 5 solutions in experiment 1, you are going…
A: When we make 10X dilution, the [H3O+] concentration of the diluted solution decreases by 10 times.…
Q: A water sample is approximated to have a total hardness equal to 120.0ppm. How many milliliters of…
A: By knowing the hardness amount on particular volume of solution we can calculate the millilitres of…
Q: Please help me answers the questions below
A: Hey, since there are multiple questions posted, we will answer first posted question. If you want…
Q: 20.0 mL water sample was titrated with 0.0100 M EDTA solution that required 14.50 mL for CaCO3…
A: Here we have to determine the hard ness of hard water interms of CaCO3 if 20 mlbof hard water sample…
Q: Question 7 A student performed three DCM layer titrations in Part 2 and they reported the following…
A:
Q: Equations: Conc/Abs1 = Conc2/Absz MW salicylic acid: 138.12 g/mol Determine the concentration of…
A:
Q: Part A Calculate the solubility (in grams per 1.00 x 102 mL of solution) of magnesium hydroxide in a…
A: Solubility product for Mg(OH)2 is given by Ksp = 5.61×10−12 Part A: Given that: pH = 12 Calculate…
Q: A 50.00-mL aliquot of solution containing 0.310 of MgSO4 (FM 120.37) in 0.500 L required 37.77 mL of…
A: Given, 50.00-mL aliquot of solution containing 0.310 g of MgSO4 (FM 120.37) in 0.500 L required…
Q: mix 500 ml of 0.1 M HCl solution with 300 ml of 2 M Ba (OH) 2 solution a) indicate the environment…
A:
Q: 2. Experiment: UV-vis experiment was done to determine the unknown concentration of an organic…
A: If 893.51 g is dissolved in 1 litre is 1M concentration Then 0.500 g dissolving in 1litre is how…
Q: the total hardness of water sample?
A:
Q: 1. A 0.1250-g sample of pure (100%) of K2Cr2O7 was dissolve in 250-mL volumetric flask, and dilute…
A: “Since you have asked multiple questions, we will solve the first question for you. If you want any…
Q: What is the average molarity of NaOH between the three trials? Titration Lab Trial 1 Trial 2 Trial 3…
A: In Trial 1 The molarity of sodium hydroxide base can be calculated as, M1=molarity of…
Q: Iron(III) chloride-thiocyanate system 1. Prepare a stock solution by adding 2 mL 0. 1 M FeCl̟ and 2…
A: A question based on equilibrium concept that is to be accomplished.
Q: PRE-LAB QUESTIONS 1. A student dissolves 2.006 g of FeSO4-7 H₂O in 40 mL of sulfuric acid and then…
A: #2(a): Mass of FeSO4.7H2O standard taken = 2.047 g Molar mass of FeSO4.7H2O = 55.845 + 32.065 +…
Q: In the titration of 25.00 mL of a water sample, it took 19.990 mL of 3.480x 10−3 M EDTA solution to…
A: we know that moles = concentration x volume (ml) / 1000 so moles of EDTA = 3.480x 10−3 * 19.990 /…
Q: The Ksp of Mg(OH)2 was determined from the following data: 0.0504 L of Mg(OH)2 solution was titrated…
A: Given, Volume of Mg(OH)2 = 0.0504 L Volume of HCl = 0.02474 L Concentration of HCl = 0.534 M
Q: 5. In our experiment, we took 5.00 ml of unknown solution consisting of Ca2+, Mg2+ to a 250 ml…
A: Quantitative analysis is used to determine the amount of analyte present in the sample. Quantitative…
Q: The color change of a chemical indicator requires an overtitration of 0.03 mL. Calculate the percent…
A:
Q: A 100 mL of 0.375 M CH3COOH solution was shaken with 1.0 g charcoal for 5 min. After filtration, 10…
A: I have given a detailed solution to the question as follows:
Q: Volume percent (v/v%) is temperature-independent. 2) There are three major approaches to expressing…
A: Dear Subscriber! You have posted multipart question. As per our policy , we answered only first…
Q: 3. What is the path length in centimeters when the molar absorptivity for a given absorbing species…
A: Given data, Molar absorptivity = 1.32 x 103Lmol-1cm-1 Concentration = 0.000923 M Absorbance = 0.490…
Q: A 1x working solution contains 50mM of EDTA. What is the EDTA concentration in your 91x concentrated…
A: Given: 1x working solution contains 50mM of EDTA.
Q: 0.00599 M EDTA solution is used to titrate 250 mL of solution formed by adding MgSO 4 to water. The…
A: A titration is a technique where a solution of known concentration is used to determine the…
Q: MISSED THIS? Watch KCV 17.4A, KCV 17.4B, IWE 17.6, IWE 17.7; Read Section 17.4. You can click on the…
A: According to the mole concept, in terms of mass, the amount of substance in moles is equal to the…
Q: If 20 mL of a hydrochloric acid solution (HCl) required 18 mL of a sodium hydroxide in a titration…
A: Given that, Volume of HCl = 20 mL Volume of NaOH required for neutralization of 20 mL HCl = 18 mL…
Q: In the titration of 25.00 mL of a water sample, it took 20.840 mL of 4.350x 10−3 M EDTA solution to…
A:
Q: Data for titration of 15.00 mL of vinegar with approximately 1.0 M NaOH. Note you must use the exact…
A: Given : 15 mL of vinegar sample is taken and titrate it with 1 M NaOH.
Q: Gravimetric Problems OH N* + 2 + 2H* ÓH DMG FM 116.12 Bis(dimethylglyoximate)nickel(II) FM 288.91 FM…
A: Gravimetric analysis: This kind of analysis in chemical science has the application in the…
Q: Calculate the volume of 0.0500 M EDTA needed to titrate 29.13 mL of 0.0598 M Mg(NO3 )2. Use a MW…
A:
Q: Find the connection among the words below and choose the letter of the word which is different.* 1.…
A: Two questions based on adsorption that is to be accomplished.
Q: In the titration of 25.00 mL of a water sample, it took 20.590 mL of 3.150x 10−3 M EDTA solution to…
A: Given: Volume of water = 25.00 mL Volume of EDTA solution = 20.590 mL Molarity of EDTA solution =…
ANSWER ASAP PLEASE
The Ca2+ in a 25.00mL of underground powder was titrated with 28.60 mL of 0.01350 M EDTA. Calculate the concentration of Ca2+ in ppm. Round off your final answer to four significant figures.
Step by step
Solved in 2 steps with 2 images
- The grid has six lettered boxes, each of which contains an item that may be used to answer the questions that follow. Items may be used more than once and there may be more than one correct item in response to a question. Place the letter(s) of the correct selection(s) on the appropriate line. Could dissolve Zn(OH)2 _____________ Could be used to prepare a buffer from __________ Halfway to the equivalence point in the titration of a weak, monoprotic acid with strong base ________ SO2-related atmospheric phenomenon __________ Species formed by a Lewis acid-base reaction ________ General condition required for precipitation to occur ________ [conj. base] = [conj. acid] in a buffer ___________A 15.00 mL sample of hard water was titrated with a 0.0150 M EDTA solution. The titration required 26.72 mL of EDTA to reach the end point. What is the total hardness concentration of the water sample in ppm?Direct titration: 10.90 ± 0.02 mL of an unknown KHP solution required 11.72 ± 0.02 mL of 0.1090 ± 0.0006 M NaOH to reach the end point. What is the concentration of KHP in the unknown solution reported with absolute uncertainty? If the unknown solution was prepared by dissolving 5.128 g of the unknown KHP (204.22 g/mol) in 100.00 mL of water, what is the weight percent of KHP in the sample?
- A 0.9092g sample of wheat flour was analyzed by Kjeldahl method. The ammonia formed was distilled into 50.00 mL of 0.05063 M HCl; a 7.46 mL back titration with 0.04917 M NaOH was required. Calculate the % protein in the flour. Input the value only. Express in 2 SF.Part A: Standardization of a Sodium Hydroxide Solution Titration 1 Titration 2 Titration 3 Mass of 125 mL flask 45.849g 46.715g 44.953g Mass of flask and KHP 46.849g 47.745g 46.003g Initial buret reading (mL) 0.5 ml 0.5 ml 0.5 ml Final buret reading (mL) 27.8 ml 26.5 ml 26.7 ml Volume of NaOH used (mL) 45.11 ml 45.06 ml 45.14 ml Calculations Titration 1 Titration 2 Titration 3 Moles of KHP Moles of NaOH Molarity of NaOH Average Molarity of NaOH: _______________A 1.43 x 10-4 L solution of 45.7 mg/mL protein was analyzed using the Kjeldahl procedure. After digestion of the protein, the liberated NH3 was collected in 9.80 mL of 0235 M HCl. The unreacted acid required 10.75 mL of a standard solution of 0.0149 M NaOH for complete titration. Calculate the weight percent of nitrogen in the protein. (Molar mass N = 14.00674 g/mol)
- A 500.0-mg sample of waste ground coffee beans used as fertilizer was digested and analyzed for nitrogen using the Kjeldahl method. After digestion, the distilled ammonia was collected in 100 mL of 0.5500 M boric acid. This solution required 19.60 mL of 0.5880 M HCI for titration to the methyl red end point. Calculate the %N in the fertilizer. Prelim Rxn: NH3 + H3BO3 --> NH4: H2BO3 Titration Rxn: NH : H2BO3 + HCI --> H3BO3 CI-2A student used a pipette to add 25 cm³ of sodium hydroxide of unknown concentration to a conical flask. The student carried out a titration to find out the volume of 0.1 mol/dm3 sulfuric acid needed to neutralise the sodium hydroxide. The following is the table of results obtained. Titration Volume of sulfuric acid used/cm³ 1 27.85 27.30 27.25 27.10 27.30 a. Write down a balanced equation for the reaction between sodium hydroxide and sulfuric acid. b. Describe the titration experimental procedure (details of washings are expected) c. Determine the average titre value and explain your choice of titre values in calculating the average. d. Determine the concentration of sodium hydroxide. e. If instead of sulfuric acid, hydrochloric acid of the same concentration was used what would you expect the average titre value to be and why?A 25.00 mL unknown water sample is titrated with a standardized 0.0140 M EDTA solution. It is determined that 8.54 mL of EDTA is required to reach the end point. The blank titre was determined to be 1.50 mL. Determine the concentration of Calcium in the water sample in ppm. (mwt. of CaCO3 = 100.0892 g/mol).
- 84 mL of 0.060 M NaF is mixed with 28 mL of 0.15 M Sr(NO3)2. Calculate the concentration of Sr2+ in the final solution. Assume volumes can be added. (Ksp for SrF2 = 2.0 × 10-10) A. 0.038 M B. 0.00012 M C. 0.015 M D. 0.045 M E. 0.075 M5. A 300.0 mg sample containing Na,CO3, NaHCO, and NaOH and inert material either alone or in some combination was dissolved and titrated with 0.1000 M HCI the titration required 24.41 ml to reach the phenolphthalein endpoint. And an additional 8.67 mL to reach the methyl red endpoint. Determine the composition of the sample and calculate the percent of each titrated component.In the titration of 25.00 mL of a water sample, it took 19.040 mL of 4.965x 10−3 M EDTA solution to reach the endpoint. Convert the number of mL of bottled water used in each sample titration to Liters. (enter your answer with 3 significant figures)