A‚A = r2 = 0.2 mABo = rị = 0.5 m= 60°Kinematic diagram, the limb dimensions are given below, thedrive link in the arm slide mechanismangular position 012 = 600and the speed of the mechanism is constant 012 = as 50 rad /s01212 = 50 rad/sare given. Do the following operations respectively.a- Write the Vector Closure Equation and bring it into scalar%3Dform.AOb- Find S13, 014 Konum by doing position analysis.c- Analyzing speed S13, 014S13Find014Bo012Ao

Given: r2 = AoA = 0.2 mr1 = Ao Bo = 0.5 mAngle : θ12 = 60∘ , θ11 = 0∘Angular velocity θ12 = 50…

Answered: AọA = r2 = 0.2 A‚Bo = r1 = 0 912 = 60°…

Engineering

Mechanical Engineering

AọA = r2 = 0.2 A‚Bo = r1 = 0 912 = 60° %3D %3D %3D %3|

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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