As a technician in a large pharmaceutical research firm, you need to produce 150. mL of a potassium dihydrogen phosphate buffer solution of pH = 6.98. The pKa of H2PO4¯ is 7.21. You have the following supplies: 2.00 L of 1.00 M KH2P04 stock solution, 1.50 L of 1.00 M K2HPO4 stock solution, and a carboy of pure distilled H2O. How much 1.00 M KH,PO4 will you need to make this solution? (Assume additive volumes.) Express your answer to three significant digits with the appropriate units. > View Available Hint(s)

Chemistry: An Atoms First Approach
2nd Edition
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
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Chapter13: Acids And Bases
Section: Chapter Questions
Problem 188IP: Isocyanic acid (HNCO) can be prepared by heating sodium cyanate in the presence of solid oxalic acid...
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nd Bases
13 of 21
<>
I Review | Constants | Periodic Table
Part A
H of
nd the
As a technician in a large pharmaceutical research firm, you need to produce 150. mL of a potassium dihydrogen phosphate buffer
solution of pH = 6.98. The pKa of H2PO4 is 7.21. You have the following supplies: 2.00 L of 1.00 M KH2PO4 stock solution, 1.50
L of 1.00 M K2HPO4 stock solution, and a carboy of pure distilled H2O.
at
ses
How much 1.00 M KH,PO4 will you need to make this solution? (Assume additive volumes.)
Express your answer to three significant digits with the appropriate units.
• View Available Hint(s)
Volume of KH2PO4 needed =
Value
Units
Transcribed Image Text:Disable nd Bases 13 of 21 <> I Review | Constants | Periodic Table Part A H of nd the As a technician in a large pharmaceutical research firm, you need to produce 150. mL of a potassium dihydrogen phosphate buffer solution of pH = 6.98. The pKa of H2PO4 is 7.21. You have the following supplies: 2.00 L of 1.00 M KH2PO4 stock solution, 1.50 L of 1.00 M K2HPO4 stock solution, and a carboy of pure distilled H2O. at ses How much 1.00 M KH,PO4 will you need to make this solution? (Assume additive volumes.) Express your answer to three significant digits with the appropriate units. • View Available Hint(s) Volume of KH2PO4 needed = Value Units
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