Assume a dictionary with some values: students = { 'CCU101': ['Anna', 88.5, 98.5, 78, 85, 92.5], "CCU102': ['Alex', 98,91,90,92,88], "CCU103': ['Bob', 99.5, 98.5, 96, 96, 89.5], } To access, a specific row, you would use students[key][column_number]. • students['CCU101'][0] would print 'Anna' students['CCU101'][1] would print 88.5

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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Assume a dictionary with some values:

students = { 'CCU101': ['Anna', 88.5, 98.5, 78, 85, 92.5], '

CCU102': ['Alex', 98,91,90,92,88],

'CCU103': ['Bob', 99.5, 98.5, 96, 96, 89.5], }

To access, a specific row, you would use students[key][column_number].

  • students['CCU101'][0] would print 'Anna'
  • students['CCU101'][1] would print 88.5

and so on..

Write a program that defines a function that takes a dict as an argument, adds the scores of each student, calculate average for each student, and display them.

 

  1. Define a function display_average(students) that takes in a dictionary as an argument. Display the original dictionary. Calculate and display the average of each student.

  2. You do not need to ask user for input. You can use your own dictionary with at-least 5 rows.

Assume a dictionary with some values:
students = {
'CCU101': ['Anna', 88.5, 98.5, 78, 85, 92.5],
"CCU102': ['Alex', 98,91,90,92, 88],
'CCU103': ['Bob', 99.5, 98.5, 96, 96, 89.5],
}
To access, a specific row, you would use students[key][column_number].
• students['CCU101'][0] would print 'Anna'
• students['CCU101'][1] would print 88.5
Transcribed Image Text:Assume a dictionary with some values: students = { 'CCU101': ['Anna', 88.5, 98.5, 78, 85, 92.5], "CCU102': ['Alex', 98,91,90,92, 88], 'CCU103': ['Bob', 99.5, 98.5, 96, 96, 89.5], } To access, a specific row, you would use students[key][column_number]. • students['CCU101'][0] would print 'Anna' • students['CCU101'][1] would print 88.5
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