Assuming that you are only using one deck, and there are only four cards on the table. If you have a 10 and a 7 showing, the dealer has a 10 showing, calculate the probability of the dealer's other card being an 8, 9, or a face card. Also, explain why it makes sense to hit on a 16 but to stand on a 17. If the house will stand on a 17 and above, how would you justify this strategy?

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A: 1) c= 302) E(X) = 1/23) V(X) = 1/28 Explanation:

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A:

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A:

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A: A box contains nine cards.Sample space: S = {J, K, L, M, N, O, P, Q, R}

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A:

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A: 95% confidence interval for true population:     0.3669 < p < 0.4531Explanation:

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A:

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