At 298K, the equilibrium constant for the following reaction is 7.50×10-3: H3PO4(aq) + H20= H30*(aq) + H2PO4¯(aq) The equilibrium constant for a second reaction is 6.20×10-8: H2PO4 (aq) + H20= H30*(aq) + HPO,2"(aq) Use this information to determine the equilibrium constant for the reaction: H3PO4(aq) + 2H20= 2H30*(aq) + HPO42-(aq) K =

At 298K, the equilibrium constant for the following reaction is 7.50×10-3: H3PO4(aq) + H20= H30(aq) + H2PO4¯(aq) The equilibrium constant for a second reaction is 6.20×10-8: H2PO4 (aq) + H20= H30(aq) + HPO,2"(aq) Use this information to determine the equilibrium constant for the reaction: H3PO4(aq) + 2H20= 2H30*(aq) + HPO42-(aq) K =

General, Organic, and Biological Chemistry

7th Edition

ISBN:9781285853918

Author:H. Stephen Stoker

Publisher:H. Stephen Stoker

Chapter9: Chemical Reactions

Section: Chapter Questions

Problem 9.76EP: Calculate the value of the equilibrium constant for the reaction N2(g)+2O2(g)2NO2(g) if the...

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