At time t = 12 s, the velocity of a particle moving in the x-y plane is v = 0.12i+2.52j m/s. By time t = 12.13 s, its velocity has become -0.06i +2.32j m/s. Determine the magnitude day of its average acceleration during this interval and the angle made by the average acceleration with the positive x-axis. The angle is measured counterclockwise from the positive x-axis. Answers: dav= 0= IM i m/s² O

At time t = 12 s, the velocity of a particle moving in the x-y plane is v = 0.12i+2.52j m/s. By time t = 12.13 s, its velocity has become -0.06i +2.32j m/s. Determine the magnitude day of its average acceleration during this interval and the angle made by the average acceleration with the positive x-axis. The angle is measured counterclockwise from the positive x-axis. Answers: dav= 0= IM i m/s² O

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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