b) State two (2) material used for rolling contact bearing.
Q: An annealed copper strip 9 in wide having. K=80,000 psi, N=0.60, and a height of 1 in _was flat…
A:
Q: Specify How to improve the structure of steel after hot rolling?
A: Hot rolling is the process of the metal is heated at high temperature and the compressed through…
Q: Why do the Ductile materials fail in shear?
A: Ductile materials are the materials which goes plastic deformation before the fracture. When any…
Q: What exactly is meant by the term "shearing stress"?
A:
Q: 3. Why single shear strength is greater than double shear?
A:
Q: Describe the strain and energy?
A: When a body is subjected to any tensile or compressive forces then the body undergoes deformation…
Q: 9) Define the rolling resistance. 10) Define the slip angle.
A: Rolling Resistance It is the resistance offered by the body when it rolls on the ground or it is…
Q: Do ductile materials fail in shear?
A: The type of materials that undergo considerable plastic deformation before fracture are known as…
Q: How does torsional stress and angle of twist impact engineering design?
A: Importance of torsional stress in Engineering Design:- Torsional stress is induced in an element due…
Q: Bar stock of initial diameter = 90 mm is drawn with a draft = 15 mm. The draw e has an entrance…
A:
Q: Give an example of the single shear failure?
A: Shear is caused by the action of two opposite and equal forces acting on a material. If the two…
Q: 1. If failure occurs in tension, why is shear important? Why is torsional load called pure shear?
A: Solution:
Q: Give an example of the Absolute Maximum Shear Strain?
A:
Q: The maximum possible draft in rolling which is the difference between initial and final thickness of…
A: Rolling is a process in manufacturing where we change the geometry of the object. In this process,…
Q: Define the term proportional limit?
A: Proportional limit: It is a point on the Stress-strain curve. Up to this point, the stress in the…
Q: Name the four basic bulk deformation processes.
A: Given:
Q: choose true or false : -The listed life of a rolling bearing, in a catalogue, is the minimum…
A: The listed life of a rolling bearing, in a catalogue, is the minimum expected life. Answer: True
Q: Define rate of linear deformation?with unit
A:
Q: q1)Work-parts that have low area to- volume ratio are called. Select one: a. Bulk b. Billets c.…
A: Given:
Q: What happens to the shear stress as flexural capacity increases?
A: It is the strength of any beam against transverse loads applied on them. It is given by 'EI', where…
Q: How was the shear formula derived?
A: Shear Stress: This is the ratio of force acting per unit area of an object/component. This is…
Q: What is Ultimate stress?
A: Ultimate Stress The ultimate stress recognizes as the maximum value of stress that a material can…
Q: Write the difference between damped and undamped vibrations?
A: Answer :- The difference between damped vibration and undamped vibration has been summarised in…
Q: What would be the result of the Yielding of the material?
A: In stress-strain curve of material the yield point is the point of elasticity. Yield points shows…
Q: what are bending moment and shear force equations?
A:
Q: Find the angle of bite
A: Given; In single pass rolling bearing process using ;Diameter,d=510 mm R=255 mmwidth,W=110So,Acc.…
Q: Which material is stronger? 250 maraging steel at room temperature (RT) or 6061 T6 aluminum sheet at…
A: Aluminium is around one-third the weight of stainless steel, which is why it's employed in…
Q: Illustrate the effect caused by the longitudinal shear stress?
A: In addition to transverse shear stresses the beam also experiences longitudinal shear stress under…
Q: Describe shear stress?
A: Shear stress When a body undergoes a load and deformation is caused by the stress that is parallel…
Q: How can I find the reactions, shear force and bending moment in this problem?
A:
Q: Give short Definition about: 1. Rolling: 2. Extrusion: 3. Strength: 4. Elasticity: 5. Plasticity:
A: Rolling and extrusion are the metal forming processes. Metal forming is a process where the…
Q: Describe distributed loadings?
A: Distributed load is a load applied across a length or area instead of at one point on a beam. If we…
Q: What is shear strength & how is it calculated?
A: There are no standard values published in the books for the shear strength. In some cases we take 60…
Q: What is centripetal force?
A: Centripetal force is a force that acts during a circular motion. During circular motion centripetal…
Q: 9) Define the rolling resistance.
A: We are to define rolling resistance.
Q: An annealed copper strip 9 in wide having . K=80,000 psi, N=0.60, and a height of 1 in _was flat…
A:
Q: 6) Chapter 3: Problem 3.7: (USCS Units) The flow curve for a certain metal has a strain-hardening…
A:
Q: Typically, the shear yield stress is what fraction of the tensile yield stress?
A:
Q: - Why single shear strength is greater than double shear?
A: Given data Why single shear strength is greater than double shear strength
Q: Hot rolling is carried at temperature lower than melting temperature of materials Select one: True O…
A:
Q: Define the term material contracts?
A: The fundamental meaning of Material Contract is any contract ( except loan documents ) which can be…
Q: What are the Linear distributed loadings and how does it produce reluctant force?
A: The loadings in which the load is not acting at one point but is spread over some length is known as…
Q: Favourable properties required for material of knife are
A: Option (c) is correct. High malleability and high strength
Q: mention the advantages and disadvantages of rolling contact bearing
A: Rolling contact bearings: In rolling contact bearings, the contact between the bearing surfaces is…
Q: what is the equation and units for finding yield stress?
A:
Q: Question 1 Choose corect statements related to the cold rolling process O Require greater loads O…
A: Cold rolling process requires greater loads due to strain hardening or work hardening of material by…
Q: Define the term initiation of yielding?
A: given: Define the term initiation of yielding?
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- Problem 2. A 300-mm diameter solid disk is to be used as a flywheel in a machine to reduce speed fluctuations. If the disk material has yield strength S Y =720 MPa, density p=7000 kg/m^ 3 . and Poisson's ratio J = 0.2 ^ c , find the maximum allowable rotational speed (in rpm) for a safety factor of 1. a) Solve using the MSST. b) Solve assuming that the disk is mad of cast iron having Sut = 207MPa , Fuc = 780MPa, p = 7000 kg/m³, and Poisson's ratio v r = 0.26 , Use Coulomb-Mohr theory.1) The rotating solid steel shaft (Fig.1 a) is simply supported by bearings at points B and C and is driven by a gear (not shown) which meshes with the spur gear at D, which has a 150 mm pitch diameter. The force F from the drive gear acts at a pressure angle of 20°. The shaft transmits a torque to point “A" of TA = 300 N.m. There is a step at point "C" as shown in Fig.1 (b), assume that D/d ratio is 1,09 and fillet radius (r) is 2,5 mm. a) Find the stress concentrations at point "C" due to bending and shear loads (Initially assume d=50mm). If the shaft is machined from quenched and drawn steel with Sy= 420 MPa and Sut=560 MPa and b) using a factor of safety of 2.5, determine the minimum allowable diameter of the shaft at "C" based on a static yield analysis using the distortion energy (DE) theory. If the shaft with a diameter (d) of 32 mm is made of a brittle material with Suc = 420 MPa and c) Sut=360 MPa, determine the factor of safety of the shaft at "C" based on a static analysis…A bevel gear is attached to a shaft supported by self-aligning bearings at A and B and is driven by a motor. The axial force, radial force, and tangential force are known. Assume the weight of the gear and shaft is negligible and that the bearing at A takes all the thrust load A) Draw (to scale) axial load, shaft torque, shear force(x-y and x-z), and bending moment(x-y and x-z)diagrams for the shaft B)Determine the values of axial load and torque along the shaft
- A 2 hp, 2500 rpm electric motor drives a machine through a flat belt. The driven shaft speed requirement equals 1000 rpm. Find a. The pitch line velocity b. The radius of the driven pulley r2 and the angle o wrap of the driving pulley c. The values of tension forces Fl and F2 Given: c- 25 in., rl - 1.5 in.,f-0.35, w=0.01 Ib/in.a) A line shaft as shown in Figure Q is driven using a motor placed vertically below it. The pulley on the line shaft is 1.6 m in diameter and has belt tensions 7.5 kN and 2.4 kN on the tight side and slack side of the belt respectively. Both tensions may be assumed to be vertical and the weight of the pulley is negligible. If the pulley is overhang from the shaft, the distance of the centre line of the pulley from the centre line of the bearing being 500 mm.6.Figure Q(i) Predict using distortion energy theory, the appropriate diameter of the shaft that failure will not occur if the yield strength, Sy = 370 Mpa and factor of safety is 2.5. (ii) Assuming the maximum allowable shear stress of 42 MPa, find its diameter using maximum shear stress theory. (iii) Comparing the diameters in (i) and (iii) above, which of them would you have used to design your shaft and why?1. Consider the slider-crank linkage shown in Fig. 1, representing a low speed compressor so that inertial effects are negligible. It is assumed that gravity forces are also small compared with the other forces and that all forces lie in the same plane. The dimensions are OB = 30 cm, and BC = 70 cm Find the required crankshaft torque Tand the bearing forces for a total gas pressure force P = 3 kN when the crank angle o = 30° crank angle Fig. 1. Slider Crank Mechanism
- 1) A ladder leans against a wall as shown below. A hammer is placed on one of the rungs (you can assume the hammer is pointlike). The ladder feels a force of friction from the ground, but there is no friction between the ladder and the wall. The length of the ladder is 20 ft The mass of the ladder 40 The inclination of the ladder 35 The height of the hammer 10 The mass of the hammer 25 (a) Write the torque balance (b) Determine the coefficient of friction between the ground and the ladder.3. A motor is connected by a belt to pulley B. T, is the tight-side tensile force equal to 1800 N. The shaft spins at a constant speed, 650 rpm. The power delivered by the motor is 12.6 kW. On pulley A, connected to the load, the slack side of the belt has a tension equal to th of the tight side. b T T, B d shaft Dimensions are as follows: da 200 тm 300 тт | 250 тm |180 тm | 250 тm 26 тm dB dahaft a We analyzed a problem similar to this on Test 01 using static failure theories. Is this strictly correct? Because the shaft is spinning, would not a material particle see a time-varying reversal of the the bending stress as in the R.R. rotating beam test? Would a particle see a reversal of the torsional shear stress? Assume Sut = 370 MPa and Sy = 300 MPa. Ignore Marin factors. Ignore stress concentrations. Ignore direct shear stress (that due to V). Find the safety factors with respect to fatigue and yielding. Be guided by section 6-14 on combined loading.mechanical engineering (Machine design) (1)Find the torque and power that a shaft with a diameter of d=50 mm can safely carry at n=200 rpm. (safe shear stress value will be taken as Sem-80N/mm² for the shaft material).
- (BB) Q1: The shaft, as shown in Fig. is driven by pulley B from an electric motor. Another belt drive from pulley A is running a compressor. The belt tensions for pulley A are 1500 N and 600 N. The ratio of belt tensions for pulley B is 2.5. The diameter of pulley A is 150 mm and the diameter of pulley B is 480 mm. The allowable shear stress for the shaft material is 85 MPa. Taking torsion and bending factors as 1.25 and 1.5 respectively, find the shaft diameter. C # -100- A B -150-100 D TB2 All dimensions in mm. B A TAZ TAI TB1D₁ B TB = 90 N-m b) 200 mm * 200 mm Tc = 30 N-m + 400 mm D₂ Side view of a shaft The side view of a stepped solid circular shaft is given below. The shaft is fixed at both ends, and two torques of TB = 90 N·m and Tc = 30 N·m are applied at points B and C, respectively. The diameters of portion AB and BD are D₁ = 30 mm and D₂ = 50 mm, respectively. Take G = 40 GPa. a) Determine the support reactions and draw the variation of the torque (torque diagram) between A and D, Find the angle of twist at point C.-8 Q2: A shaft is driven by a motor which exerts a constant torque while the load taken off the shaft fluctuates from zero to maximum during each revolution. If the maximum fluctuating in energy in one cycle is AE=242 N.m. Find the moment of inertia of the flywheel (I) to be mounted on the shaft so that the speed fluctuating shall not be more than 3 r.p.m. above or below a .mean speed of N=200 r.p.m