b Use curved arrows to show the mechanism of the step below. Make the ends of your arrows specify the origin and destination of reorganizing electrons. Arrow-pushing Instructions :0=C=0: べ 2+ Mg Br
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- Step 6: When a curved arrow starts from a o bond and points to a distant atom, the o bond breaks and a new o bond is formed. А — В А—С В В —С A or Note that two possible cations can be formed, depending on whether the electrons from the o bond move with atom A or B. Draw curved arrows to form the products shown. Select Draw Rings More Erase +H -H Reset Drawing H H | H- + AIH3 H - AL H H :o :kindly answer from C to EDraw curved arrows and identify the thermal and photochemical products of the electrocyclic reaction of (2Z,4Z,6E)-octa-2,4,6-triene. Step 2: An electrocyclic reaction will undergo a concerted electron shift to form a cyclic ring. A new sigma bond will be formed between carbons 2 and 7. The product will be neutral. (2ZAZ,6E)-octa-2,4,6-triene Draw the curved arrows to show the mechanism. Select Draw Rings More Erase
- Shown below is a carbocation intermediate in an electrophilic addition reaction of HCl with an alkene. For the conformation shown, select each hydrogen whose bond to carbon is aligned for effective hyperconjugation with the vacant p orbital on the positively charged carbon. Each adjacent carbon will have only one C-H bond so aligned. • Gray = C; white = H; red = 0; blue = N; dark green = Cl; brown =Br; light green =F; purple = I; yellow = S; orange = P. • Double click to select atoms. • You can zoom in and out using the mouse scroll wheel (or pinch to zoom on touch screens).Circle 1: E1 or E2? KOt-Bu А. Е1 E2 Br H20 E1 E2 heat Br MeO С. Е1 E2 heat Br B.Practice Problem 03.46b SH +. +. HOH 3.46b1 For the reaction given below, draw a mechanism (curved arrows) and then predict which side of the reaction is favored under equilibrium conditions. 奏一 HE KC 美C Edit 00
- Please help with row 2/question 2 ; the instructions for the specific column in row 2 are above row 1: Follow the instructions in each column. Hint for the last column: draw it with a wedge and again with adash – which gives the correct configuration?CrO3 CH3CH2CH2OH CH3CH2COH CH3CH2COCH2CH2CH3 A problem often encountered in the oxidation of primary alcohols is that esters are sometimes produced as by-products. For example, oxidation of propyl alcohol yields propanoic acid and propyl propanoate. Draw curved arrows to show the movement of electrons in this step of the reaction mechanism. Arrow-pushing Instructions B: :0: CH3CH2CH- A: BH* CH;CH,CH нӧ: HÖ H-AAdd a propoxy substituent at position #2, an isopropyl substituent at position #3, and a methyl substituent at position #9 to this organic molecule. Make sure to use the same skeletal ("line") drawing style when adding your substituents. Try again Jean E 民 مله Ar
- 5. Which of the following is True and which one is False? The IR spectrum of 1-hexene has more peaks than its UV spectrum. The n---π for acrolein (CH2=CH=O) has shifted to a shorter wavelength, compared to propanal.Consider the structure that results from the ring inversion of the chair conformation below. Add the substituent required to the given cyclohexane ring to show this structure. Be sure to use guide points when adding substituents. H₂C. 0 to 0:0 3 ←1) a until g
