Answered: BenzoicacidhasaKa of6.46x10 . What is…

Chemistry: Principles and Reactions

8th Edition

ISBN:9781305079373

Author:William L. Masterton, Cecile N. Hurley

Publisher:William L. Masterton, Cecile N. Hurley

Chapter14: Equilibria In Acid-base Solutions

Section: Chapter Questions

Problem 70QAP: Consider the titration of HF (K a=6.7104) with NaOH. What is the pH when a third of the acid has...

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BenzoicacidhasaKa of6.46x10 .

What is the pH of the solution that results when 25.0 mL of 0.300 M benzoic acid are titrated with 20.0 mL of 0.200 M KOH?

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Step 1

The number of moles of benzoic acid, KOH, and the concentration of KOH and benzoic acid is calculated as shown below.

$\begin{array}{rcl} n_{KOH} & = & 20.0 mL \times 0.200 M \times \frac{1.0 L}{1000.0 mL} \\ = & 0.004 mol \\ n_{Benzoic acid} & = & 25.0 mL \times 0.300 M \times \frac{1.0 L}{1000.0 mL} \\ = & 0.0075 mol \\ V_{T} & = & 45 mL \\ M_{KOH} & = & \frac{0.004 mol}{45 mL} \times \frac{1000 mL}{1.0 L} \\ = & 0.089 M \\ M_{Benzoic acid} & = & \frac{0.0075 mol}{45 mL} \times \frac{1000 mL}{1.0 L} \\ = & 0.167 M \end{array}$

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