Benzyl bromide (C6H5CH2Br) reacts rapidly with CH3OH to afford benzyl methyl ether (C6H5CH2OCH3). Draw a stepwise mechanism for the reaction, and explain why this 1° alkyl halide reacts rapidly with a weak nucleophile under conditions that favor an SN1 mechanism. Would you expect the para-substituted benzylic halides CH3OC6H4CH2Br and O2NC6H4CH2Br to each be more or less reactive than benzyl bromide in this reaction? Explain your reasoning.

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Q: What type of product would form when LDA( strong base/weak nucleophile) is reacted with( methyl…

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Q: F

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Q: Which alkyl halide in each pair will undergo the faster SN2 reaction?

A: Given:

Q: + 2 å NaOH

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Q: Arrange the Alkyl chlorides in the order of reactivity in SN2 reaction 1-chlorobutane CI…

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A:

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Q: Which compounds, for each pair, will be more reactive towards a nucleophile. Illustrate and explain…

A: Welcome to bartleby !

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Reactions at the Alpha Carbon Atom

The position next to the ketone or aldehyde functional group is termed as alpha position and the reaction which occurs at alpha position is called alpha substitution reaction. In an alpha substitution reaction, the alpha proton atom is substituted by an electrophile by the formation of an enol intermediate or enolate ion intermediate. Most of the carbonyl compounds go through an alpha substitution reaction.