Block 1 (m1 = 10 kg) and block 2 (m2 = 9 kg) are adjacent to each other on the surface of a table. Block 2 is to the LEFT of block 1. A hand pushes horizontally on block 2 and causes both blocks to move to the right with an acceleration of magnitude 3 m/s2. The coefficient of kinetic friction between the block and the surface equals 0.6. Use g = 10 m/s2. On a sheet of paper, draw the free body diagrams for block 1 and block 2 using the two-subscript notation from class. After completing the free body diagrams, enter below each force and its x & y-components. Remember that the x-component is the "i" component and the y-component is the "j" component. NET force on Block 1 Fnet1 = i + j N NET force on Block 2 Fnet2 = i + j N Tries 0/2 FORCES on BLOCK 1 Weight force on block 1 by Earth W1E = i + j N Normal force on block 1 by Surface N1S = i + j N Frictional force on block 1 by Surface f1S = i + j N Normal force on block 1 by block 2 N12 = i + j N Tries 0/2 FORCES on BLOCK 2 Weight force on block 2 by Earth W2E = i + j N Normal force on block 2 by Surface N2S = i + j N Frictional force on block 2 by Surface f2S = i + j N Normal force on block 2 by block 1 N21 = i + j N Normal force on block 2 by Hand N2H = i + j N
THERE IS NO DIAGRAM IN THE PROBLEM***
***3 SUBPARTS**
***3 SUBPARTS***
Block 1 (m1 = 10 kg) and block 2 (m2 = 9 kg) are adjacent to each other on the surface of a table. Block 2 is to the LEFT of block 1. A hand pushes horizontally on block 2 and causes both blocks to move to the right with an acceleration of magnitude 3 m/s2. The coefficient of kinetic friction between the block and the surface equals 0.6. Use g = 10 m/s2.
On a sheet of paper, draw the free body diagrams for block 1 and block 2 using the two-subscript notation from class. After completing the free body diagrams, enter below each force and its x & y-components. Remember that the x-component is the "i" component and the y-component is the "j" component.
NET force on Block 1
Fnet1 = i + j N
NET force on Block 2
Fnet2 = i + j N
Tries 0/2 |
FORCES on BLOCK 1
Weight force on block 1 by Earth
W1E = i + j N
Normal force on block 1 by Surface
N1S = i + j N
Frictional force on block 1 by Surface
f1S = i + j N
Normal force on block 1 by block 2
N12 = i + j N
Tries 0/2 |
FORCES on BLOCK 2
Weight force on block 2 by Earth
W2E = i + j N
Normal force on block 2 by Surface
N2S = i + j N
Frictional force on block 2 by Surface
f2S = i + j N
Normal force on block 2 by block 1
N21 = i + j N
Normal force on block 2 by Hand
N2H = i + j N
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