help f. Calculate AG and the exponent value (the x of 10) for K, for the following reactions at 25°C:(a) Mg(s) + Pb2 (aq) Mg2"(aq) + Pb(s)AG: -430.3x:75(b) O2(g) + 4H"(aq) + 4FE2*(aq) = 2H,0(1) + 4Fe*(aq)AG":-177.5x:31(c) 2AI(s) + 31,(8) = 2A1*(aq) + 6I (aq)AG":-131.2x: 23 Standard Reduction Potentiaisin Aqueous Solutions at 25 °CReductionOxidizing AgentReducing AgentPotential (V)F2H,O2MnO,2е2F2.872H* + 2e2H20Mn2+ + 4H201.788H* + 5e¯1.51Au3+3eAu1.50+Cl2O2Cr,0,2- +Br2NO3Ag*12+2e-1.364H+ + 4e2H202Cr3+ + 7H2O1.2314H+ + 6e-1.232e2Br1.07NO + 2H20Ag+4H* + 3e0.96e0.80+2e21-0.54Cu*+e-Cu0.52O2Cu2+2H,0 + 4e2e2e+4OH-0.40+Cu0.342H30* +Pb2+Sn2+H2 + 2H,00.00+2ePb-0.132eSn-0.14Ni2+Fe2+Cro+Zn2+2eNi-0.26+2eFe-0.45ЗеCr-0.74ZnH2 + 20H-+2e-0.762H,0Mn2+2e-0.832eMn-1.19A3+3eAI-1.66Mg²+NaCa2+Ba2++2eMg-2.37eNa-2.712e2eСа-2.87Ва-2.91K*eK-2.93Li*eLi-3.04Increasing Strength of Oxidizing Agent- + + + + +↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑Increasing Strength of Reducing Agent

Answered: Image /qna-images/answer/2ae6aac5-a1ea-4101-a091-068d366282f0.jpg

Calculate AG and the exponent value (the x of 10) for K, for the following reactions at 25°C: (a) Mg(s) + Pb2 (aq) = Mg²"(aq) + Pb(s) AG":-430.3 x:75 (b) O2(g) + 4H (aq) + 4FE2 (aq) = 2H,0(1) + 4Fe"(aq) AG:-177.5 x:31 (c) 2Al(s) + 31,(8) 2A*(aq) + 61 (aq) AG":-131.2 x: 23

Calculate AG and the exponent value (the x of 10) for K, for the following reactions at 25°C: (a) Mg(s) + Pb2 (aq) = Mg²"(aq) + Pb(s) AG":-430.3 x:75 (b) O2(g) + 4H (aq) + 4FE2 (aq) = 2H,0(1) + 4Fe"(aq) AG:-177.5 x:31 (c) 2Al(s) + 31,(8) 2A*(aq) + 61 (aq) AG":-131.2 x: 23

Principles of Modern Chemistry

8th Edition

ISBN:9781305079113

Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Chapter14: Chemical Equilibrium

Section: Chapter Questions

Problem 15P

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Question

help f.

Calculate AG and the exponent value (the x of 10) for K, for the following reactions at 25°C:
(a) Mg(s) + Pb2 (aq) Mg2"(aq) + Pb(s)
AG: -430.3
x:75
(b) O2(g) + 4H"(aq) + 4FE2*(aq) = 2H,0(1) + 4Fe*(aq)
AG":-177.5
x:31
(c) 2AI(s) + 31,(8) = 2A1*(aq) + 6I (aq)
AG":-131.2
x: 23

Standard Reduction Potentiais
in Aqueous Solutions at 25 °C
Reduction
Oxidizing Agent
Reducing Agent
Potential (V)
F2
H,O2
MnO,
2е
2F
2.87
2H* + 2e
2H20
Mn2+ + 4H20
1.78
8H* + 5e¯
1.51
Au3+
3e
Au
1.50
+
Cl2
O2
Cr,0,2- +
Br2
NO3
Ag*
12
+
2e-
1.36
4H+ + 4e
2H20
2Cr3+ + 7H2O
1.23
14H+ + 6e-
1.23
2e
2Br
1.07
NO + 2H20
Ag
+
4H* + 3e
0.96
e
0.80
+
2e
21-
0.54
Cu*
+
e-
Cu
0.52
O2
Cu2+
2H,0 + 4e
2e
2e
+
4OH-
0.40
+
Cu
0.34
2H30* +
Pb2+
Sn2+
H2 + 2H,0
0.00
+
2e
Pb
-0.13
2e
Sn
-0.14
Ni2+
Fe2+
Cro+
Zn2+
2e
Ni
-0.26
+
2e
Fe
-0.45
Зе
Cr
-0.74
Zn
H2 + 20H-
+
2e
-0.76
2H,0
Mn2+
2e
-0.83
2e
Mn
-1.19
A3+
3e
AI
-1.66
Mg²+
Na
Ca2+
Ba2+
+
2e
Mg
-2.37
e
Na
-2.71
2e
2e
Са
-2.87
Ва
-2.91
K*
e
K
-2.93
Li*
e
Li
-3.04
Increasing Strength of Oxidizing Agent
- + + + + +
↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑
Increasing Strength of Reducing Agent

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