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Calculate AG at 600. K for H₂O(g) + 1/2 O2(g) = H₂O2(g) using the following data: AG° = H2(g) + O2(g) H₂O2(g) K= 1.8 x 10³7 at 600. K 2H2(g) + O2(g) → 2H₂O(g) K = 2.3 x 106 at 600. K kJ/mol

Calculate AG at 600. K for H₂O(g) + 1/2 O2(g) = H₂O2(g) using the following data: AG° = H2(g) + O2(g) H₂O2(g) K= 1.8 x 10³7 at 600. K 2H2(g) + O2(g) → 2H₂O(g) K = 2.3 x 106 at 600. K kJ/mol

Principles of Modern Chemistry
Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter14: Chemical Equilibrium
Section: Chapter Questions
Problem 15P
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Calculate AGO at 600. K for H₂O(g) + 1/2 02(g) H₂O2(g) using the following data: AGO H₂(g) +O2(g) → H₂O2(g) K = 1.8 × 10³7 at 600. K ← 2H2(g) + O2(g) 2H₂O(g) K = 2.3 × 106 at 600. K Ş kJ/mol
Transcribed Image Text:Calculate AGO at 600. K for H₂O(g) + 1/2 02(g) H₂O2(g) using the following data: AGO H₂(g) +O2(g) → H₂O2(g) K = 1.8 × 10³7 at 600. K ← 2H2(g) + O2(g) 2H₂O(g) K = 2.3 × 106 at 600. K Ş kJ/mol
At what temperatures will the following processes be spontaneous? (Enter NONE if the process is never spontaneous, and ALL if it is always spontaneous in BOTH blanks in a row.) a. AH = -17 kJ and AS = -60. J/K At temperatures b. AH = +17 kj and AS = +60. J/K At temperatures c. AH = +17 kJ and AS = -60. J/K At temperatures d. AH = -17 kJ and AS = +60. J/K At temperatures K K K K
Transcribed Image Text:At what temperatures will the following processes be spontaneous? (Enter NONE if the process is never spontaneous, and ALL if it is always spontaneous in BOTH blanks in a row.) a. AH = -17 kJ and AS = -60. J/K At temperatures b. AH = +17 kj and AS = +60. J/K At temperatures c. AH = +17 kJ and AS = -60. J/K At temperatures d. AH = -17 kJ and AS = +60. J/K At temperatures K K K K
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