Calculate the energy released for the consumption of 350mL of 6.5 M LIOH in the following neutralization reaction with the given heat of neutralization. LIOH(aq) + HCI(aq) – LICI(s) + H;O(E) AH° = -18.61 kl/mol A 42.34 k) B) 42,337 k) -42.34 k) -42,337 k)

Chemistry for Engineering Students
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Author:Lawrence S. Brown, Tom Holme
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Chapter12: Chemical Equilibrium
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Calculate the energy released for the consumption of 350mL of 6.5 M LIOH in the following neutralization reaction with the given
heat of neutralization.
LIOH(aq) + HCI(aq) – LICI(s) + H;O(E)
AH° = -18.61 kl/mol
A
42.34 k)
B) 42,337 k)
-42.34 k)
-42,337 k)
Transcribed Image Text:Calculate the energy released for the consumption of 350mL of 6.5 M LIOH in the following neutralization reaction with the given heat of neutralization. LIOH(aq) + HCI(aq) – LICI(s) + H;O(E) AH° = -18.61 kl/mol A 42.34 k) B) 42,337 k) -42.34 k) -42,337 k)
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