Calculate the equilibrium partial pressure of H₂. 0.167 atm Part 4rt Determine the equilibrium partial pressure of H2₂O after CO and H₂ at 0.0790 atm are added to the equilibrium mixture described above. 0.32683 atm Part 5 are Determine the equilibrium partial pressure of CO after the addition described above. 5.1972 Part 6 atm See Hint Determine the equilibrium partial pressure of H₂ after the addition described above. 0.513 atm

Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter15: Principles Of Chemical Reactivity: Equilibria
Section: Chapter Questions
Problem 3PS: Kc = 5.6 1012 at 500 K for the dissociation of iodine molecules to iodine atoms. I2(g) 2 I(g) A...
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Part 3
Calculate the equilibrium partial pressure of H₂.
0.167
atm
Part 4rt
Determine the equilibrium partial pressure of H₂O after CO and H₂ at
0.0790 atm are added to the equilibrium mixture described above.
0.32683
atm
Part 5 are
Determine the equilibrium partial pressure of CO after the addition
described above.
5.1972
Part 6
atm
See Hint
Determine the equilibrium partial pressure of H₂ after the addition
described above.
0.513
atm
Transcribed Image Text:Part 3 Calculate the equilibrium partial pressure of H₂. 0.167 atm Part 4rt Determine the equilibrium partial pressure of H₂O after CO and H₂ at 0.0790 atm are added to the equilibrium mixture described above. 0.32683 atm Part 5 are Determine the equilibrium partial pressure of CO after the addition described above. 5.1972 Part 6 atm See Hint Determine the equilibrium partial pressure of H₂ after the addition described above. 0.513 atm
Only Part 6
The water-gas reaction is a source of hydrogen. Passing steam over hot carbon
produces a mixture of carbon monoxide and hydrogen.
H₂O(g) + C(s) = CO(g) + H₂(g)
The value of K, for the reaction at 1000.0°C is 3.00 x 10-².
4th attempt
3
Part Prt
Part 2 2e-
Calculate the equilibrium partial pressure of H₂O given that PH20 = 0.442
atm and Pco= 5.000 atm at the start of the reaction. Assume that the
carbon is in excess.
0.275
atm
See Periodic Table
Calculate the equilibrium partial pressure of CO.
5.167
atm
Transcribed Image Text:Only Part 6 The water-gas reaction is a source of hydrogen. Passing steam over hot carbon produces a mixture of carbon monoxide and hydrogen. H₂O(g) + C(s) = CO(g) + H₂(g) The value of K, for the reaction at 1000.0°C is 3.00 x 10-². 4th attempt 3 Part Prt Part 2 2e- Calculate the equilibrium partial pressure of H₂O given that PH20 = 0.442 atm and Pco= 5.000 atm at the start of the reaction. Assume that the carbon is in excess. 0.275 atm See Periodic Table Calculate the equilibrium partial pressure of CO. 5.167 atm
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