Calculate the mean and 90% confidence interval for the data set. Sample Value 8.0626 8.0650 3 8.0583 4 8.0564 8.0571 6. 8.0600 mean: 山T四月@ stv A hulu
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- Sample IdentificationCodeConcentration of M%TA=2-log(%T)Q50004.00 x 10-417.90.75Q50013.20 x 10-425.00.6Q50022.40 x 10-435.70.46Q50031.60 x 10-450.20.3Q50048.000 x 10-570.80.15SampleIdentificationCode%TA=2-log(%T)AMQ0210150143.70.359518560.360.000192Q0210150244.10.355561410.360.00018Q0210150343.80.358525890.360.00017Q0210150444.10.355561410.360.00018Q0210150543.80.358525890.360.00017What was their percent error?43%Does Batch 021015 meet legal requirements?No, because it is not between 2.85 * 10(4) and 3.15 * 10(4)Well #DropsBluedye1234567891012345678910Drops 9Distilled water876543210Concne 0.26tration0.52Test Tube #0.781.041.3Solutions3Concentration (M)2.082.32.6Concentration (ppm)1:1 dilution11.82Starting Dilution21.562:1 dilution0A.Zero standard0Was your calibration curve as linear as you expected?B.Did you experience any âdriftâ of the resistance readings?C.What is the equation of your best-fit line?D.What commercial drink did you analyze?E.Assuming…In the technique of high performance liquid chromatography (HPLC) the peak area response for a particular analyte is directly proportional to concentration Analgesic tablets typically consist of aspirin and caffeine as the active ingredients, the remainder made up of inert binding material. The concentrations of aspirin and caffeine may be routinely monitored using HPLC, whereby the peak areas obtained from a solution of the tablet are compared with those obtained from standard solutions of the analytes. In an analysis to determine the concentration of caffeine in such a tablet, the following data were recorded: Solutions Analysed: Tablet Sample: Mass of tablet (dissolved in 250 cm methano): 0.523 g Caffeine Standard: Mass of caffeine (diessolved in 500 cm methanol) 0.105 g HPLC results: Solution Peak Area (catfeine) 1. Tablet Sample 325 2. Caffeine Std. 865 The concentration of caffeine in the tablet (expressed as a mass (w/wl percentage) was Oa 1.89 Ob 13.4 O 3.77 Od. 267 Oe 7.54 You…The ages of a group of 122 randomly selected adult females have a standard deviation of 18.5 years Assume that the ages of female statistics students have less variation than ages of females in the general population, so let o = 18 5 years for the sample size caloulation How many female statistics student ages must be obtained in order to estimate the mean age of all female statistics students? Assume that we want 95% confidence that the sample mean is within one-half year of the population mean. Does it seem reasonable to assume that the ages of female statistics students have less variation than ages of females in the general population? The required sample size is (Round up to the nearest whole number as needed)
- An analysis of city drinking water for total hardness was done by two students in the laboratory and produced the following results (in ppm CaCO3): Student A: 228.3, 226.4, 226.9, 227.1, and 228.6. Student B: 229.5, 226.1, 230.7, 223.8, and 227.5What is the 95% confidence interval for the mean?Plot the following data and perform linear regression to obtain the value of the slope, the value of the y-intercept, and the correlation coefficient r. x- axis y-axis ln(0) 4.6052 0.0000 3.8712 0.6931 3.4012 1.0986 2.7081 1.3863 2.1972 1.6094 1.7918 1.7918 1.0986 1.9459 0.0000The following molarities were calculated from replicate standardization of a solution: 0.5021, 0.5015, 0.5035, 0.5007, 0.504, 0.5025, and 0.5008 M. Assuming no determinate errors, what is the upper limit of the 95% confidence interval?
- Apply the Q test to the following data sets to determine whether the outlying result should be retained or rejected at the 95% confidence level. a. 85.10, 84.62, 84.70b. 85.10, 84.62, 84.65, 84.702. The following values were obtained from the calibration of a 10mL pipet 10.28, 9.99, 10.12, and 9.63 mL. Calculate the mean value and the standard deviation from the mean.Using the data given below, determine the relationship between Sstd and Cstd using an unweighted linear regression. Cstd (arbitrary units) Sstd(arbitrary units) KA= Sstd! C std 0.000 0.00 0.100 12.36 123.6 0.200 24.83 124.2 0.300 35.91 119.7 0.400 48.79 122.0 0.500 60.42 122.8 Calculate the 95% confidence intervals for the slope and y-intercept.
- 4. A new method for the determination of mercury in fish was tested against a N.I.S.T. standard to determine if there was any bias (determinate error) in the new technique. The N.I.S.T. standard fish sample was certified to contain 13.55 ppm Hg. The results of six analyses by the new method gave a mean value of 14.15 ppm and s.d. = 0.42 ppm. Does the new method give accurate results at the 95% confidence level?The following molarities were calculated from replicate standardization of a solution: 0.5, 0.5002, 0.501 ,0.5025,0.5022,0.5024 0.5013, upper limit of the 95% confidence interval?What is the relative average deviation in the following percent KHP values in ppt? 46.80% 47.23% 48.03%