Calculate the percent ionization of a 0.125-M solution of nitrous acid (a weak acid), with a pH of 2.09. Solution % acid ionization = [H3Oleq x 100 [HA]. NOTE 1: if you're given the pH, then [H3O+] = [H*]eq = 10-PH !!! eq % acid ionization = 10-2.09 x 100 = 6.50% 0.125 NOTE 2: % lonization IS the 5% Rule!!! Thus, if we wanted to know the EQUILIBRIUM concentration of HNO₂, we would need to subtract 10-PH from 0.125 M to get 0.117 M
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![Calculate the percent ionization of a 0.125-M solution of nitrous acid (a weak acid), with a pH of 2.09.
Solution
% acid ionization = [H3Oleq x 100
[HA].
NOTE 1: if you're given the pH, then [H3O+] = [H*]eq = 10-PH !!!
eq
% acid ionization = 10-2.09 x 100 = 6.50%
0.125
NOTE 2: % lonization IS the 5% Rule!!! Thus, if we wanted to know the
EQUILIBRIUM concentration of HNO₂, we would need to subtract 10-PH from 0.125
M to get 0.117 M](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F637a8243-98d2-45ca-8dd1-4e9d7d0f97ca%2F63d77140-d983-4e71-8f37-43c2f07609b2%2Frvpcod5.jpeg&w=3840&q=75)
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