Mg(s) + 2HCl(a) →MgCl₂ (aq) + H₂(g)-0.024= 29.6ml.= 0.996 ATM= 297KData SheetExperimental Values1. Mass (weight) of Mg ribbon2. Volume of wet gas (V₁)3. Barometric pressure (V₁)4. Temperature of water and gas (7)5.Vapor pressure of water at6.Height of water (Ah)7. Pressure of H₂O (P)8. Pressure of gas (if dry)256.92 torr24°C°C24= Ah/13.6Pg=Pb-Pwy-PwCalculated Values1. Volume of H, if it was collected at STP2. No. of equivalents of H₂ (11.2 L @ STP = 1 equiv.)3. No. of equivalents of Mg needed to produce the above4. Equivalent weight of Mg (no. g of Mg/no. of equiv.)5. Valence of Mg (valence = atomic weight/equiv. weight)6. % error in the equivalent weight*valence is equivalent to oxidation statePwy22.38274P.= 20.15=714.37||||||||||||8torrmmtorrtorr= 0.939 ATMmLequiv.equiv.g/equiv.%

To calculated the following values from the given experimental values: (1) Volume of hydrogen gas…

Calculated Values 1. Volume of H₂ if it was collected at STP 2. No. of equivalents of H₂ (11.2 L@STP = 1 equiv.) 3. No. of equivalents of Mg needed to produce the above (no. g of Mg/no. of equiv.) atomic weight/equiv. weight) 4. Equivalent weight of Mg 5. Valence of Mg (valence 6. % error in the equivalent weight *valence is equivalent to oxidation state ##### ml. equiv. equiv. g/equiv. %

Calculated Values 1. Volume of H₂ if it was collected at STP 2. No. of equivalents of H₂ (11.2 L@STP = 1 equiv.) 3. No. of equivalents of Mg needed to produce the above (no. g of Mg/no. of equiv.) atomic weight/equiv. weight) 4. Equivalent weight of Mg 5. Valence of Mg (valence 6. % error in the equivalent weight *valence is equivalent to oxidation state ##### ml. equiv. equiv. g/equiv. %

Chemistry: Principles and Reactions

8th Edition

ISBN:9781305079373

Author:William L. Masterton, Cecile N. Hurley

Publisher:William L. Masterton, Cecile N. Hurley

Chapter10: Solutions

Section: Chapter Questions

Problem 89QAP

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Similar questions

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